Question

我有一张这样的表：

ID    Name
----------
1   john
1   molly
2   greg
2   sean
1   holly
2   mill

SQL Query应该如何聚合结果，如下所示：

ID  Name
-------------
1   john/molly/holly
2   greg/sean/mill

Answer 1

注意：STUFF函数只是从返回的字符串中删除了前导/。

SELECT t1.id, 
       STUFF((SELECT '/' + t2.name
                FROM YourTable t2
                WHERE t1.id = t2.id
                ORDER BY t2.name
                FOR XML PATH('')),1,1,'') AS Name
    FROM YourTable t1
    GROUP BY t1.id

用于聚合/连接的SQL查询

1 个答案: