Question

我有一个三列表，其中列出了每个人，他们可能参加过的每个活动，以及他们在那里的时间百分比。我真的想在一个页面上显示这个，旁边是人名，顶部是事件名。

这是'我拥有的一个例子：

NAME    EVENT       %ATTENDANCE
Smith   Rock Climbing   50
Allen   Rock Climbing   78
Moore   Rock Climbing   100
Moore   Canoeing    100
Moore   Fencing     98
Moore   Archery     34
Allen   Archery     100
Allen   Canoeing    87

这就是我想要展示的内容。

NAME    ROCK CLIMBING   CANOEING    FENCING     ARCHERY
Smith   50      -       -       -
Allen   75      87      -       100
Moore   100     100     98      34

Answer 1

select Name, [Rock Climbing],[Canoeing],[Fencing],[Archery]
from 
(select * from YourTable) p
pivot
(
  SUM(Attendance)
  for Event in ( [Rock Climbing], [Canoeing],[Fencing],[Archery] ) 
)
as pvt

参考：http://msdn.microsoft.com/en-us/library/ms177410.aspx

Answer 2

WITH tAttendance (Name, Event, Attendance)
AS
(
    SELECT 'Smith', 'Rock Climbing', 50 UNION ALL
    SELECT 'Allen', 'Rock Climbing', 78 UNION ALL
    SELECT 'Moore', 'Rock Climbing', 100 UNION ALL
    SELECT 'Moore', 'Canoeing', 100 UNION ALL
    SELECT 'Moore', 'Fencing', 98 UNION ALL
    SELECT 'Moore', 'Archery', 34 UNION ALL
    SELECT 'Allen', 'Archery', 100 UNION ALL
    SELECT 'Allen', 'Canoeing', 87 
)

SELECT Name
,(SELECT COALESCE(CAST(SUM(Attendance)AS varchar),'-')FROM tAttendance t2 WHERE t1.Name=t2.Name AND Event='Rock Climbing')AS [Rock Climbing]
,(SELECT COALESCE(CAST(SUM(Attendance)AS varchar),'-')FROM tAttendance t2 WHERE t1.Name=t2.Name AND Event='Canoeing')AS Canoeing
,(SELECT COALESCE(CAST(SUM(Attendance)AS varchar),'-')FROM tAttendance t2 WHERE t1.Name=t2.Name AND Event='Fencing')AS Fencing
,(SELECT COALESCE(CAST(SUM(Attendance)AS varchar),'-')FROM tAttendance t2 WHERE t1.Name=t2.Name AND Event='Archery')AS Archery
FROM tAttendance t1
GROUP BY Name
Order By SUM(Attendance)

注意：第一部分仅用于测试。不是很灵活的方法，但可能适合你。

结果：

Name    Rock Climbing   Canoeing     Fencing    Archery
Smith        50            -            -          -
Allen        78            87           -         100
Moore       100           100          98          34

从不同的值生成列

2 个答案: