Question

我通过使用JSoup执行2 for循环来解析来自网站的2个元素，TD标记。我希望它们在Listview中彼此相邻显示，如下所示：

naam: waarde 
naam: waarde

但它们在Listview中显示如下，由CustomBaseAdapter填充。

naam: 
naam: 
naam: 
waarde 
waarde 
waarde

有人可以帮我完成这件事吗？这让我忙着一段时间退出。

欢迎任何其他建议，谢谢。

2 for for循环，用“naam”和“waarde”填充列表：

 Document doc = Jsoup.parse(kpn);  
   Elements tdsFromSecondColumn = doc.select("table.personaltable td:eq(0)"); 
   Elements tdsFromSecondColumn1 = doc.select("table.personaltable td:eq(1)"); 
   SearchResults sr1 = new SearchResults(); 

      for (Element tdFromSecondColumn : tdsFromSecondColumn) {                            
           sr1 = new SearchResults(); 
           sr1.setNaam(tdFromSecondColumn.text()); 
           results.add(sr1); 
      } 

      for (Element tdFromSecondColumn1 : tdsFromSecondColumn1) {                              
           sr1 = new SearchResults(); 
           sr1.setWaarde(tdFromSecondColumn1.text()); 
           results.add(sr1); 
      }

我知道它应该是这样的，但是如何？：

for (Element tdFromSecondColumn : tdsFromSecondColumn) {                             
     sr1 = new SearchResults();  
     sr1.setNaam(tdFromSecondColumn.text());  
     sr1.setWaarde(tdFromSecondColumn1.text());
     results.add(sr1);

}

这是我的CustomeBaseAdapter：

public class MyCustomBaseAdapter extends BaseAdapter { 

private static ArrayList<SearchResults> searchArrayList; 

private LayoutInflater mInflater; 


  public MyCustomBaseAdapter(Context context, ArrayList<SearchResults> results) { 
  searchArrayList = results; 
  mInflater = LayoutInflater.from(context); 
  } 


public int getCount() { 
  return searchArrayList.size(); 
} 

public Object getItem(int position) { 
  return searchArrayList.get(position); 
} 

public long getItemId(int position) { 
  return position; 
} 

public View getView(int position, View convertView, ViewGroup parent) { 
    ViewHolder holder; 
  if (convertView == null) { 
    convertView = mInflater.inflate(R.layout.test, null); 
    holder = new ViewHolder(); 
    holder.txtNaam = (TextView) convertView.findViewById(R.id.naam); 
    holder.txtWaarde = (TextView) convertView.findViewById(R.id.waarde); 

    convertView.setTag(holder); 
   } else { 
 holder = (ViewHolder) convertView.getTag(); 
 } 

 holder.txtNaam.setText(searchArrayList.get(position).getNaam()); 
 holder.txtWaarde.setText(searchArrayList.get(position).getWaarde()); 

 return convertView; 
} 

static class ViewHolder { 
  TextView txtNaam; 
  TextView txtWaarde; 
} 


}

编辑：我现在有点像这样但得到异常indexsize 12：

public ArrayList<SearchResults> GetSearchResults(){

          ArrayList<SearchResults> results = new ArrayList<SearchResults>();
          ArrayList<SearchResults> results1 = new ArrayList<SearchResults>();
          ArrayList<SearchResults> results2 = new ArrayList<SearchResults>();

          Document doc = Jsoup.parse(kpn);  
          Elements tdsFromSecondColumn = doc.select("table.personaltable td:eq(0)");
          Elements tdsFromSecondColumn1 = doc.select("table.personaltable td:eq(1)");

          SearchResults sr1 = new SearchResults();
          SearchResults sr2 = new SearchResults();


          for (Element tdFromSecondColumn : tdsFromSecondColumn) {                             
               sr1 = new SearchResults();  
               sr1.setNaam(tdFromSecondColumn.text());  
               results.add(sr1);  
          }  

          for (Element tdFromSecondColumn1 : tdsFromSecondColumn1) {                               
               sr2 = new SearchResults();  
               sr2.setWaarde(tdFromSecondColumn1.text());  
               results1.add(sr2);  
          }  

          for (int i = 0; i < results.size();i++) { 
              results.add(results.get(i));
              results2.add(results1.get(i)); 
            } 

          return results2;

         }
     }

EDIT2：异常消失但它只显示了结果1 i.a setWaarde：

public ArrayList<SearchResults> GetSearchResults(){

          ArrayList<SearchResults> results = new ArrayList<SearchResults>();
          ArrayList<SearchResults> results1 = new ArrayList<SearchResults>();
          ArrayList<SearchResults> results2 = new ArrayList<SearchResults>();

          Document doc = Jsoup.parse(kpn);  
          Elements tdsFromSecondColumn = doc.select("table.personaltable td:eq(0)");
          Elements tdsFromSecondColumn1 = doc.select("table.personaltable td:eq(1)");

          SearchResults sr1 = new SearchResults();
          SearchResults sr2 = new SearchResults();


          for (Element tdFromSecondColumn : tdsFromSecondColumn) {                             
               sr1 = new SearchResults();  
               sr1.setNaam(tdFromSecondColumn.text());  
               results.add(sr1);  
          }  

          for (Element tdFromSecondColumn1 : tdsFromSecondColumn1) {                               
               sr1 = new SearchResults();  
               sr1.setWaarde(tdFromSecondColumn1.text());  
               results1.add(sr1);  
          }  

          for (int i = 0; i < results.size() && i < results1.size();i++) { 
              results.add(results.get(i));
              results2.add(results1.get(i)); 
            } 

          return results2;

         }
     }

Answer 1

问题是每次循环时都要创建一个新的SearchResults对象。在第一个循环的每次迭代期间创建一个SearchResults对象是很好的，但是你需要使用在第一个循环中为第二个循环创建的SearchResults对象，不要创建一个新对象。 / p>

Answer 2

克里斯所说的+1。此外，如果您尝试组合这两个循环，则无法使用该语法执行此操作。只需使用简单的计数方法，例如

for(Object o : oList1) {
    doStuff(o);
}

for (Object o : oList2) {
    doStuff2(o);
}

成为

for (int i = 0; i < oList1.size() && i < oList2.size(); i++) {
    doStuff(oList1.get(i));
    doStuff2(oList2.get(i));
}

当然，这假设两个列表的长度相同，否则其中一个列表将不会被完全消耗。如果它们不同，你可以在循环中使用OR代替AND，并在对它们进行操作之前检查每个是否为null，但是你最好只使用两个独立的循环。

Answer 3

得到了它的工作！，在接受了kcoppock的建议后退了一会儿，喝了啤酒和香烟，解决方案就像我想的那样容易：

public ArrayList<SearchResults> GetSearchResults(){

          ArrayList<SearchResults> results = new ArrayList<SearchResults>();

          Document doc = Jsoup.parse(kp);  
       // Get all td's 
          Elements waardes= doc.select("td"); 
       // Iterator over those elements      
          ListIterator<Element> postIt = waardes.listIterator(); 

          SearchResults sr1 = new SearchResults();

          while (postIt.hasNext()) { 
                sr1 = new SearchResults();
                // Add the value text to the ArrayList      
                sr1.setNaam(postIt.next().text()); 
                sr1.setWaarde(postIt.next().text());  
                results.add(sr1); 
            } 

          return results;

         }
     }

结合2 for循环

3 个答案: