添加页面旁边的前一个(后退)和下一个按钮编号PHP

时间:2011-10-25 12:32:14

标签: php button pagination back next

我有两个小问题;

1。我想在此代码中添加上一个/下一个按钮 2。我希望它只显示前一个和下一个之间的最多10个链接。因此,如果我有50个数字/链接,它将只显示10个,而不是页面上的50个链接。

我在clo上搜索了

代码有效,只需要两个选项。 有人可以帮我吗?谢谢!

 <?php 

        include 'includes/connection.php';  
        $per_page = 8;

        $pages_query = mysql_query("SELECT COUNT(`id`) FROM `products`");
        $pages = ceil(mysql_result($pages_query, 0) / $per_page);

        $page = (isset($_GET['page'])) ? (int)$_GET['page'] : 1;
        $start = ($page - 1) * $per_page;



        $query = mysql_query("SELECT `name` FROM `products` LIMIT $start, $per_page");
        while ($query_row = mysql_fetch_assoc($query)) {
            echo '<p>', $query_row['name'] ,'</p>';
        }

        if ($pages >= 1 && $page <= $pages) {
            for ($x=1; $x<=$pages; $x++) { 
                //echo $x, ' '; 

                echo ($x == $page) ? '<strong><a href="?page='.$x.'">'.$x.'</a></strong> ' : '<a href="?page='.$x.'">'.$x.'</a> ';
            }
        }else{
            header("location:index.php?page=1");
        }


    ?>

2 个答案:

答案 0 :(得分:1)

答案 1 :(得分:1)

首先,你应该,只是为了良好的做法,放一个“退出”;在header()之后调用。它在这个特定的脚本中没有什么区别,但请记住,在重定向之前,将执行标题(“Location:...”)调用之后的任何代码。

现在回答您的问题,试试这个(更新:此代码已经过测试并且有效。)

<?php 
include 'includes/connection.php';  
$per_page = 8;
$pages_query = mysql_query("SELECT COUNT(`id`) FROM `products`");
$pages = ceil(mysql_result($pages_query, 0) / $per_page);

$page = (isset($_GET['page'])) ? (int)$_GET['page'] : 1;
$start = ($page - 1) * $per_page;

$query = mysql_query("SELECT `name` FROM `products` LIMIT $start, $per_page");
while ($query_row = mysql_fetch_assoc($query))
{
    echo '<p>' . $query_row['name'] . '</p>';
}

// If the requested page is less than 1 or more than the total number of pages
// redirect to the first page
if($pages < 1 || $page > $pages)
{
    header('Location: ?page=1');
    // end execution of the rest of this script
    // it will restart execution after redirection
    exit;   
}
// If more than one page, show pagination links
if($pages > 1)
{
    $html = array();
    $html[] = '<strong>';
    // if you're on a page greater than 1, show a previous link
    $html[] = (($page > 1) ? '<a href="?page=' . ($page - 1) . '">Previous</a> ' : '');
    // First page link
    $pageFirst = '<a href="?page=1">1</a>';
    $html[] = (($page == 1) ? "</strong>{$pageFirst}<strong>" : $pageFirst);

    if ($pages > 6)
    {
        $start_cnt = min(max(1, $page - (6 - 1)), $pages - 6);
        $end_cnt = max(min($pages, $page + 4), 8);

        $html[] = ($start_cnt > 1) ? '...' : ' ';

        for ($i = $start_cnt + 1; $i < $end_cnt; $i++)
        {
            $html[] = ($i == $page) ? '</strong><a href="?page=' . $i . '">' . $i . '</a><strong>' : '<a href="?page=' . $i . '">' . $i . '</a>';
            if ($i < $end_cnt - 1)
            {
                $html[] = ' ';
            }
        }

        $html []= ($end_cnt < $pages) ? '...' : ' ';
    }
    else
    {
        $html[] = ' ';

        for ($i = 2; $i < $pages; $i++)
        {
            $html[] = ($i == $page) ? '</strong><a href="?page=' . $i . '">' . $i . '</a><strong>' : '<a href="?page=' . $i . '">' . $i . '</a>';
            if ($i < $pages)
            {
                $html[] = ' ';
            }
        }
    }
    // last page link
    $pageLast = '<a href="?page=' . $pages . '">' . $pages . '</a>';
    $html[] = (($page == $pages) ? "</strong>{$pageLast}<strong>" : $pageLast);
    // Show next page link if you're on a page less than the total number of pages
    $html[] = ($page < $pages) ? ' <a href="?page=' . ($page + 1) . '">Next</a>' : '';
    // If you're not on the last page, show a next link
    $html[] = '</strong>';
}
else
{
     // show page number 1, no link.
    $html[] = '<strong>1</strong>';
}
echo implode('', $html);

还要注意最终?&gt;

,在PHP代码之后没有HTML代码的PHP文件中不需要这样做。