Question

当读取包含<xs:redefine>标记的模式并尝试使用模式集编译它时，我得到以下异常：

'SchemaLocation' must successfully resolve if <redefine>
contains any child other than <annotation>

我尝试了许多不成功的解决方法，例如递归地解析模式并在编译之前将它们添加到模式集中，甚至将它们添加为引用。架构仍然无法编译。尝试的内容示例（解析主xsd，然后在调用此递归函数后尝试编译生成的'XmlSchemas'）：

private void AddRecursive (XmlSchemas xsds, XmlSchema schema)
{
    foreach (XmlSchemaExternal inc in schema.Includes) {
        String schemaLocation = null;
        schemaLocation = inc.SchemaLocation;
        XmlSchema xsd;
        using (FileStream stream = new FileStream (schemaLocation, FileMode.Open, FileAccess.Read)) {
            xsd = XmlSchema.Read (stream, null);
            xsds.Add (xsd);
            xsds.AddReference (xsd);
        }
        AddRecursive (xsds, xsd);
    }
}

处理此类架构的正确方法是什么？为什么模式编译器不能解析添加的模式本身？

Answer 1

使用基于Stream的重载读取XML模式的问题在于XML Schema reader没有可用的基础uri。如果您的xsd：redefine在schemaLocation属性中使用相对URI，则默认解析程序将无法找到正在重新定义的模式 - 因此您将收到错误消息。

我正在为您提供以下配置，以帮助您前进，至少在理解这是如何工作的时候。将两个模式和测试脚本保存在同一文件夹中，更新脚本中的路径并运行C＃脚本。它会给你这个输出：

QN: http://tempuri.org/XMLSchema.xsd:TRedefine, SourceUri: file:///D:/.../.../Redefine.xsd
QN: http://www.w3.org/2001/XMLSchema:anyType, SourceUri:

如果您更新脚本以使用基于流的重载，您将从帖子中收到错误消息。

Error line 20:      xset.Add(XmlSchema.Read(File.Open    (@"D:\...\...\Redefine.xsd", FileMode.Open), null));
    'SchemaLocation' must successfully resolve if <redefine> contains any child other than     <annotation>.
'SchemaLocation' must successfully resolve if <redefine> contains any child other than     <annotation>.
Error Line 21: xset.Add(XmlSchema.Read(File.Open    (@"D:\...\...\Redefine.xsd", FileMode.Open), null));

基本架构：

<?xml version="1.0" encoding="utf-8" ?>
<xsd:schema targetNamespace="http://tempuri.org/XMLSchema.xsd"
    elementFormDefault="qualified"
    xmlns="http://tempuri.org/XMLSchema.xsd"
    xmlns:xsd="http://www.w3.org/2001/XMLSchema">
    <xsd:complexType name="TRedefine">
        <xsd:sequence>
            <xsd:element name="base" type="xsd:string"/>
        </xsd:sequence>
    </xsd:complexType>
</xsd:schema>

重新定义的架构：

<?xml version="1.0" encoding="utf-8"?>
<!--XML Schema generated by QTAssistant/XSR Module (http://www.paschidev.com)-->
<xsd:schema xmlns="http://tempuri.org/XMLSchema.xsd" attributeFormDefault="unqualified"     elementFormDefault="qualified" targetNamespace="http://tempuri.org/XMLSchema.xsd"     xmlns:xsd="http://www.w3.org/2001/XMLSchema">
    <!-- Put a full path here.
  <xsd:redefine schemaLocation="D:\...\...\Base.xsd">
    -->
    <xsd:redefine schemaLocation="Base.xsd">
        <xsd:complexType name="TRedefine">
            <xsd:complexContent>
                <xsd:extension base="TRedefine">
                    <xsd:sequence/>
                </xsd:extension>
            </xsd:complexContent>
        </xsd:complexType>
    </xsd:redefine>
</xsd:schema>

测试脚本：

using System;
using System.IO;
using System.Xml;
using System.Xml.Schema;
class Script
{
    public static void Main()
    {
        // Enter your code below
        // Generated by QTAssistant (http://www.paschidev.com)
        XmlSchemaSet xset = new XmlSchemaSet();

        // One way of doing using an XmlReader - it'll work with relative URIs.
        using(XmlReader reader = XmlReader.Create(@"D:\...\...\Redefine.xsd"))
        {
            xset.Add(XmlSchema.Read(reader, null));
        }

        // The other way, using stream, requires all external URIs - xsd:include,     xsd:import and xsd:redefine 
        // to be absolute
        //xset.Add(XmlSchema.Read(File.Open(@"D:\...\...\Redefine.xsd", FileMode.Open), null));

        xset.Compile();
        Console.WriteLine(xset.IsCompiled);
        foreach(XmlSchemaType type in xset.GlobalTypes.Values) 
        {
            Console.WriteLine("QN: {0}, SourceUri: {1}", type.QualifiedName,     type.SourceUri);
        }
    }
}

Answer 2

带有XmlDocument的亲戚路径的工作示例：

        XmlReaderSettings settings = new XmlReaderSettings();
        settings.ValidationType = ValidationType.Schema;
        // It won't add schemas without XmlUrlResolver
        settings.Schemas.XmlResolver = new XmlUrlResolver();
        // Optional namespace
        var namespace = null;
        settings.Schemas.Add(namespace, "absolutePath.xsd");

        using (XmlReader reader = XmlReader.Create(sourcePath, settings))
        {
            XmlDocument document= new XmlDocument();
            document.Load(reader);
            //...
        }

在C＃中编译包含重定义的模式

2 个答案: