Question

尝试让Restlet继续使用AppEngine作为第三方json / xml服务的反向代理。

AppEngine版本1.5.5
Restlet GAE版本2.1RC1

我在我的web.xml中设置了Restlet，如下所示：

<servlet>
<servlet-name>RestletServlet</servlet-name>
<servlet-class>org.restlet.ext.servlet.ServerServlet</servlet-class>
 <init-param>
   <param-name>org.restlet.application</param-name>
   <param-value>be.koma.server.MyApplication</param-value>
 </init-param>
</servlet>
<servlet-mapping>
 <servlet-name>RestletServlet</servlet-name>
 <url-pattern>/api/*</url-pattern>
</servlet-mapping>

我将以下jar添加到WEB-INF / lib，GAE版本2.1RC1

org.json.jar
org.restlet.ext.crypto.jar
org.restlet.ext.gae.jar
org.restlet.ext.gwt.jar
org.restlet.ext.jackson.jar
org.restlet.ext.json.jar
org.restlet.ext.net.jar
org.restlet.ext.servlet.jar
org.restlet.ext.xml.jar
org.restlet.jar

这是be.koma.server.MyApplication;

的实现

public class MyApplication extends Application {

    @Override
    public Restlet createInboundRoot() {

        Router router = new Router(getContext());

        String target = "http://otherservice.com/users.xml";
        Redirector redirector = new Redirector(getContext(), target, Redirector.MODE_SERVER_OUTBOUND);
        router.setDefaultMatchingMode(Router.MODE_FIRST_MATCH);

        getConnectorService().getClientProtocols().add(Protocol.HTTP);

        router.attachDefault(redirector);

        return router;
    }
}

从我的浏览器或curl调用otherservice.com可以正常工作。

当我调用Restlet时，我得到404，因为无法找到客户端协议??

Oct 24, 2011 9:36:22 AM org.restlet.engine.log.LogFilter beforeHandle
FINE: Processing request to: "http://127.0.1.1:8888/api/otherservice/users.xml"
Oct 24, 2011 9:36:22 AM org.restlet.engine.component.HostRoute score
FINER: Call score for the "org.restlet.routing.VirtualHost@e3e496a" host: 1.0
Oct 24, 2011 9:36:22 AM org.restlet.engine.component.ServerRouter logRoute
FINE: Default virtual host selected
Oct 24, 2011 9:36:22 AM org.restlet.engine.component.HostRoute beforeHandle
FINE: Base URI: "http://127.0.1.1:8888". Remaining part: "/api/otherservice/users.xml"
Oct 24, 2011 9:36:22 AM org.restlet.routing.TemplateRoute score
FINER: Call score for the "/api" URI pattern: 0.5909091
Oct 24, 2011 9:36:22 AM org.restlet.routing.Router logRoute
FINE: Selected route: "/api" -> be.koma.server.MyApplication@668b1967
Oct 24, 2011 9:36:22 AM org.restlet.routing.TemplateRoute beforeHandle
FINER: 4 characters were matched
Oct 24, 2011 9:36:22 AM org.restlet.routing.TemplateRoute beforeHandle
FINE: New base URI: "http://127.0.1.1:8888/api". New remaining part: "/otherservice/users.xml"
Oct 24, 2011 9:36:22 AM org.restlet.routing.TemplateRoute beforeHandle
FINER: Delegating the call to the target Restlet
Oct 24, 2011 9:36:22 AM org.restlet.routing.TemplateRoute score
FINER: Call score for the "" URI pattern: 0.5
Oct 24, 2011 9:36:22 AM org.restlet.routing.Router logRoute
FINE: The default route was selected
Oct 24, 2011 9:36:22 AM org.restlet.routing.TemplateRoute beforeHandle
FINER: No characters were matched
Oct 24, 2011 9:36:22 AM org.restlet.routing.Redirector handle
INFO: Redirecting via client dispatcher to: http://otherservice.com/users.xml
Oct 24, 2011 9:36:22 AM org.restlet.engine.component.ClientRoute score
FINER: Call score for the "[WAR]" client: 0.0
Oct 24, 2011 9:36:22 AM org.restlet.routing.Router logRoute
FINE: The default route was selected
Oct 24, 2011 9:36:22 AM org.restlet.engine.component.ClientRouter getNext
WARNING: The protocol used by this request is not declared in the list of client connectors. (HTTP/1.1)
Oct 24, 2011 9:36:22 AM org.restlet.engine.log.LogFilter afterHandle
INFO: 2011-10-24    07:36:22    127.0.0.1       127.0.1.1   8888    GET /api/otherservice/users.xml -   404 439 0   28  http://127.0.1.1:8888   Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/535.1 (KHTML, like Gecko) Ubuntu/11.10 Chromium/14.0.835.202 Chrome/14.0.835.202 Safari/535.1   http://127.0.1.1:8888/test.html?gwt.codesvr=127.0.1.1:9997

有什么想法吗？关于如何调试的建议？我错过了什么见解，这看起来如此微不足道？

Answer 1

对于Restlet邮件列表上的Jerome，额外的init参数解决了这个问题：

<servlet>
    <servlet-name>RestletServlet</servlet-name>
    <servlet-class>org.restlet.ext.servlet.ServerServlet</servlet-class>
    <init-param>
        <param-name>org.restlet.application</param-name>
        <param-value>be.koma.server.MyApplication</param-value>
    </init-param>
    <init-param>
        <param-name>org.restlet.clients</param-name>
        <param-value>HTTP HTTPS</param-value>
    </init-param>
</servlet>

更多信息 http://www.restlet.org/documentation/snapshot/gae/ext/org/restlet/ext/servlet/ServerServlet.html

AppEngine上的反向代理（restlet 2.1）：404 - 缺少客户端协议

1 个答案: