Question

我的表中有这些数据：

onum    amt         odate                       cnum    snum

3001    18,69       1990-03-10 00:00:00.000     2008    1007
3002    1900,10     1990-03-10 00:00:00.000     2007    1004
3003    767,19      1990-03-10 00:00:00.000     2001    1001
3005    5160,45     1990-03-10 00:00:00.000     2003    1002
3006    1098,16     1990-03-10 00:00:00.000     2008    1007
3007    75,75       1990-03-10 00:00:00.000     2004    1002
3008    4723,00     1990-05-10 00:00:00.000     2006    1001
3009    1713,23     1990-04-10 00:00:00.000     2002    1003
3010    1309,95     1990-06-10 00:00:00.000     2004    1002
3011    9891,88     1990-06-10 00:00:00.000     2006    1001

我需要得到这个结果：

amt         odate                       snum

5160,45     1990-03-10 00:00:00.000     1002
4723,00     1990-05-10 00:00:00.000     1001
9891,88     1990-06-10 00:00:00.000     1001

即我在amt每天选择最大odate，但显示卖家snum

如果我写这个：

 SELECT MAX(amt), odate, snum 
 FROM [Understanding].[dbo].[Orders] 
 GROUP BY odate, snum

输出错误，因为它按天和卖家显示组。

Answer 1

;with C as
(
  select amt,
         odate,
         snum,
         row_number() over(partition by odate order by amt desc) as rn
  from Orders
)
select amt,
       odate,
       snum
from C
where rn = 1

Answer 2

select a.*,b.snum
from
(
select MAX(amt) as amt
      ,odate 
from Orders
group by odate
)A INNER JOIN Orders B
ON A.amt = b.amt
order by a.odate

有趣的SQL查询

2 个答案: