我正在学习如何使用SELECT CASE,但我不太了解,这里是代码:
SET @vgls=1;
SET @lgls=1;
SET @st=SELECT CASE
WHEN @vgls=@lgls THEN "emp"
WHEN @vgls>@lgls THEN "loc"
WHEN @vgls<@lgls THEN "vis" END;
SELECT @st;
它给了我以下错误:
[Err] 1064 - You have an error in your SQL syntax; check the manual that corresponds to you MySQL server version for the right syntax to use near 'SELECT CASE
WHEN @vgls=@lgls THEN "emp"
WHEN @vgls>@lgls THEN "loc"
WHEN @vg' at line 1
答案 0 :(得分:6)
您需要使用SELECT ... INTO
SELECT
...
INTO var_name [, var_name]]
而不是set
将SELECT的结果赋给变量。所以这应该这样做:
SELECT CASE
WHEN @vgls=@lgls THEN "emp"
WHEN @vgls>@lgls THEN "loc"
WHEN @vgls<@lgls THEN "vis" END
INTO @st;