Question

这很难解释我想要什么，所以我会尽我所能。

我有一个游戏，游戏中的玩家有健康计数器（hp）和保镖。每个保镖都有100马力，一旦所有球员保镖都消失了，伤害就会从他们的马力上消失。

所以，这些是我的价值观：

$dmg // the damage
$bgs // the amount of bodyguards the player has
$bg_hp // the bodyguards health. Starts at 100, drains with $dmg fired at
$hp // the players health

当他们被枪杀时，需要检查他们是否有$ bgs。这是一个基本的例子。

if ($bgs > 0) {
  $bgs_hp = $bgs_hp - $dmg;
     if ($bg_hp <= 0) { $bg = $bg - 1; $bg_hp = 100; }
  } else {
  $hp = $hp - $dmg;
  }

无论如何，我需要帮助的部分就是这个。我希望伤害重叠。所以说$ dmg是200，会杀死2个保镖（每个都有100马力）。或者有人可以射击所有他们的保镖，剩下的$ dmg也从$ hp中脱落。

我需要帮助的原因是因为我在数学方面很糟糕，而且我需要使用一些MOD函数或者某些东西。

实例;

1）球员有3名保镖。有人向他射击150 dmg。它会杀死1名保镖，并对下一次造成50点伤害。

2）玩家有一个半保镖（50）的保镖。有人向他射击160，它会杀死保镖（50hp），其余的伤害（110）也会杀死玩家。

Answer 1

我只是保留一个带有每个保镖的hps的数组，如下所示：

$bgs = array(100); // one bg with 100 hp

或

$bgs = array(100, 300, 50); // one bg with 100 hp, then one with 300, etc

如果你想知道有多少保镖，一个简单的count($bgs)会告诉你。

这将使您将来更容易扩展游戏，并且还可以更轻松地解决这些类型的计算。你现在可以写：

$hp = 100;
$bgs = array(100, 100);
$damage = 101; // for example

// As long as there's still damage to take and bgs to take it:
while($damage && !empty($bgs)) {
    $soak = min($bgs[0], $damage); // not more than the first bg can take
    $bgs[0] -= $soak; // remove hps from the first bg
    $damage -= $soak; // deduct from the amount of damage to tage
    if ($bgs[0] == 0) {
        // bodyguard dead, remove him from the array
        array_shift($bgs);
    }
}

// If there's any damage left over, it goes to hp
$hp -= $damage;

<强> See it in action

更新：这是适用于您当前方案的代码。它并不简单，而且对你能做的事情有更多的限制：

$max_bg_health = 100;
$hp = 100;
$bgs = 2;
$bg_hp = $max_bg_health; // so that makes 2 "full health" bgs
$damage = 101; // for example
if($bgs) {
    $bg_capacity = ($bgs - 1) * $max_bg_health + $bg_hp;
    $soak = min($bg_capacity, $damage);
    $bg_capacity -= $soak;
    $damage -= $soak;

    // update bodyguard status; this is extra tricky because $bgs is not
    // "the amount of full hp bgs" (which would make it a lot simpler)
    // but "the amount of bgs including the one which may not have full hp"
    $bgs = $bg_capacity ? intval($bg_capacity - 1 / $max_bg_health) + 1 : 0;
    $bg_hp = $bg_capacity % $max_bg_health;
}

// If there's any damage left over, it goes to hp
$hp -= $damage;

Answer 2

一种可能性是，仅存储总健康点（即您和保镖的健康点）。然后，您可以在每次需要时计算您的健康点数和保镖数量（因此您无需保存）

$totalhp = 499; // you have 100 health and 4 bodyguards, the last one has 99 health

$bgs = $totalhp > 100 ? (int)(($totalhp-1)/100) : 0; // Number of active bodyguards
$hp = min($totalhp, 100); // Your health
$bg_hp = $bgs > 0 ? ((($totalhp-1) % 100) + 1) : 0; // the health of your "current" bodyguard

然后，当你受到一些伤害时，只需从$totalhp：

中减去它

$totalhp = $totalhp - $dmg;

Answer 3

<?php

$bg = 2;

$health_max = 100;

$health_total = $bg * $health_max + $health_max;

$damage = 100;

if($damage >= $health_total)
{
    die('You are caput.');
}
else
{
    $health_total = $health_total - $damage;
    $bg = floor($health_total / $health_max);
}

if($bg > 0)
{
    $tmp = ($health_total - $health_max) % $health_max;
    for($i = 1; $i < $bg; $i++)
        $bg_health[] = $health_max;
    $bg_health[] = $tmp;
    $bg_health = implode(', ', $bg_health);
}

if(empty($bg_health)) $tmp = 0;
$health = $health_total - $tmp;

echo "You have {$health} health and {$bg} bodyguards left with health of {$bg_health}.";
?>

这会产生......

你有100个健康和1个保镖，健康状况为77.

php数学循环查询

3 个答案: