为什么这不插入http://但不插入http://

时间:2011-10-22 17:12:56

标签: jquery ajax json codeigniter

我需要插入site_title,site_address(网址)site_description& site_category从前端使用jquery / json进入我的数据库..如果我没有在site_address输入字段中输入“http://”,它会插入网站并更新前端,但是只要我这样做,它就会不是对数据库的帮助..

我有这段代码

主页视图中的表格:

<form action="" method="post" class="addsite_form">
  <input id="account_id" type="hidden" value="<?php echo $this->session->userdata('account_id');?>"/>
  <label for="site_title"><strong>Site Name:</strong></label> 
  <input id="site_title" type="text" maxLength="25" tabindex="1" name="site_title" /> 
  <label for="site_address"><strong>Site Address:</strong></label> 
  <input id="site_address" type="text" tabindex="2" name="site_address" /> 
  <label for="site_description"><strong>Site Description:</strong></label> 
  <input id="site_description" type="text" tabindex="3" name="site_description" /> 
  <label for="site_category"><strong>Site Category:</strong></label> 
  <input id="site_category" type="text" tabindex="4" name="site_category" /> 

  <input id="addsite_form_submit" type="submit" value="Add Site" name="submit" tabindex="5" /> 

</form>

CONTROLLER

public function addUserSites() {

  $account_id = $this->input->post('account_id');
  $site_title = $this->input->post('site_title');
  $site_description = $this->input->post('site_description');
  $site_address = $this->input->post('site_address');
  $site_category = $this->input->post('site_category');

  $array = array(
    'account_id' => $account_id,
    'site_title' => $site_title,
    'site_description' => $site_description,
    'site_address' => $site_address,
    'site_category' => $site_category,

  );

  echo json_encode($this->usersites_model->insertsites($array));

}

MODEL:

public function insertsites($data)  {

  $this->db->insert('usersites', $data);

  return TRUE; 

}

JQUERY

$('.addsite_form').submit(function() {
  var account_id = $("#account_id").val();
  var site_title = $("#site_title").val();
  var site_address = $("#site_address").val();
  var site_description = $("#site_description").val();
  var site_category = $("#site_category").val();

  $.post("/usersites/addusersites", { 

    "account_id" : account_id,
    "site_title" : site_title, 
    "site_address" : site_address, 
    "site_description" : site_description, 
    "site_category" : site_category, 
  },

  function(data){
  }, "json");
});

编辑 - 解决方案

首先,我要非常感谢 Marshall Brekka 谁建议使用encodeURIComponent ..我现在已经阅读了它并找到了php版本..

我已将urlencode添加到我的控制器中,它现在可以运行..这是新控制器

    public function addUserSites() {

    $account_id = $this->input->post('account_id');
    $site_title = $this->input->post('site_title');
    $site_description = $this->input->post('site_description');
    $site_address = $this->input->post(urlencode('site_address'));//added urlencode
    $site_category = $this->input->post('site_category');

    $array = array(
        'account_id' => $account_id,
        'site_title' => $site_title,
        'site_description' => $site_description,
        'site_address' => $site_address,
        'site_category' => $site_category,

    );

  echo json_encode($this->usersites_model->insertsites($array));

}

我可以说,我认为那些投票的人投了我的问题,无论他们站在筹码溢出社区有多高,都需要更多!我是一个菜鸟,我还在学习,我不能去大学学习这个,我有时需要帮助..你是不是在那个阶段? Pffft!

1 个答案:

答案 0 :(得分:1)

可能是因为您没有对您的值进行网址编码,请尝试此操作。

$.post("/usersites/addusersites", { 

    "account_id" : account_id,
    "site_title" : site_title, 
    "site_address" : encodeURIComponent(site_address), 
    "site_description" : site_description, 
    "site_category" : site_category, 
},