指针和opengl绘图的麻烦

时间:2011-10-21 19:22:38

标签: objective-c c pointers opengl-es

我正在尝试实现一个简单的rendermanager。另一个类提供了一个表示四边形的结构,并将其复制到rendermanager中的顶点数组缓冲区中。

然而复制似乎不起作用,当我手动创建一个结构并复制到顶点阵列时,一切都很好并且呈现。但在副本的某个地方,一切都会出错。我可以使用gdb看到这个(值不同),但我无法弄清楚发生了什么。

RenderManager方法

-(id)init
{
    if([super init]){
        iva = calloc(MAX_QUADS, sizeof(quad));

        quad draw = {
            0.0f,0.0f,0.0f,          0.0f,0.0f,1.0f,    //Bottom left
            1.0f,0.0f,0.0f,          0.0f,0.0f,1.0f,    //Top Left
            1.0f,1.0f,0.0f,          0.0f,0.0f,1.0f,    //Top Right
            0.0f,1.0f,0.0f,          0.0f,0.0f,1.0f,    //Bottom Right

            0.5f,0.5f,0.0f,          0.0f,0.0f,1.0f,    //Center
        };

如果我发表评论,没有任何内容。使用它,我得到了我期待的好四边形

        memcpy(iva, &draw, sizeof(draw)); 
        . . . OpenGl methods

//Add the quad details to the render queue
-(void)addDetailsToRenderQueue:(quad *)details
{
    if(iva == NULL)
        NSLog(@"Error claiming memory, something is very wrong");

    if(renderCount + 1 > MAX_QUADS){
        NSLog(@"Render buffer full, dumping...");
        [self render];
    }

    memcpy((quad *)iva + renderCount++, &details, sizeof(quad));
}

//Render the details in the render queue, for each quad we need to make two triangles.
-(void)render
{
    int counter = 0;

    renderCount *= 5;

    for(int i;i < renderCount;){
        ivaIndices[counter++] = i + 0;     // Bottom left
        ivaIndices[counter++] = i + 1;     //Top Left
        ivaIndices[counter++] = i + 4;      //Center

        ivaIndices[counter++] = i + 1;      //Top Left
        ivaIndices[counter++] = i + 2;      //Top right
        ivaIndices[counter++] = i + 4;      //Center

        ivaIndices[counter++] = i + 2;      //Top right
        ivaIndices[counter++] = i + 3;      //Bottom right
        ivaIndices[counter++] = i + 4;      //Center

        ivaIndices[counter++] = i + 3;      //Bottom right
        ivaIndices[counter++] = i + 0;      //Bottom Left
        ivaIndices[counter++] = i + 4;      //Center

        i += 5;
    }
    glBindVertexArrayOES(_vertexArray);

    glDrawElements(GL_LINE_STRIP,12, GL_UNSIGNED_SHORT, ivaIndices);

    // Reset the number of quads which need to be rendered
    renderCount = 0;
}   

平铺管理员方法

@interface TileSet : NSObject
{
    quad *tiles;
    NSUInteger tileCount;

    RenderManager *sharedRenderManager;
}

-(id)init
{
    if([super init]){
        tiles = calloc(MAX_HEIGHT * MAX_WIDTH, sizeof(quad));
        tileCount = 0;

        sharedRenderManager = [RenderManager sharedManager];
    }
    [self fillArray];
    return self;
}

-(void)fillArray
{   
    int rows = 4;
    int columns = 12;

    for(int i = 0; i < rows;i += 2) { 
        for(int j = 0;j < columns;j += 2) {
            quad tmp;

            tmp.v1.x = i;
            tmp.v1.y = j;
            tmp.v1.z = 0.0f;
            tmp.v1.nx = 0.0f;
            tmp.v1.ny = 0.0f;
            tmp.v1.nz = 1.0f;

            tmp.v2.x = i + 1;
            tmp.v2.y = j;
            tmp.v2.z = 0.0f;
            tmp.v2.nx = 0.0f;
            tmp.v2.ny = 0.0f;
            tmp.v2.nz = 1.0f;

            tmp.v3.x = i;
            tmp.v3.y = j+1;
            tmp.v3.z = 0.0f;
            tmp.v3.nx = 0.0f;
            tmp.v3.ny = 0.0f;
            tmp.v3.nz = 1.0f;

            tmp.v4.x = i + 1;
            tmp.v4.y = j+1;
            tmp.v4.z = 0.0f;
            tmp.v4.nx = 0.0f;
            tmp.v4.ny = 0.0f;
            tmp.v4.nz = 1.0f;

            tmp.v5.x = i + 0.5;
            tmp.v5.y = j + 0.5;
            tmp.v5.z = 0.0f;
            tmp.v5.nx = 0.0f;
            tmp.v5.ny = 0.0f;
            tmp.v5.nz = 1.0f;

            memcpy((quad *)tiles + (i*j + j), &tmp, sizeof(quad));
            tileCount++;
        }
    }
}

//Draw the tiles in the tileset, loop through and add to renderManagers queue
-(void)render
{
for(int i = 0; i  < tileCount;i++)
    [sharedRenderManager addDetailsToRenderQueue:&tiles[0]];

} 

修改 在回答问题时,添加

NSLog(@"Tiles:%x\tDisgusting pointer math:%x",tiles,(quad *)tiles + (i*j + j));

给出结果

2011-10-21 21:29:21.456 TerrainRendering[11293:fb03] Tiles:7316200  Disgusting pointer math:7316200
2011-10-21 21:29:21.458 TerrainRendering[11293:fb03] Tiles:7316200  Disgusting pointer math:73162f0
2011-10-21 21:29:21.463 TerrainRendering[11293:fb03] Tiles:7316200  Disgusting pointer math:73163e0
2011-10-21 21:29:21.464 TerrainRendering[11293:fb03] Tiles:7316200  Disgusting pointer math:73164d0
2011-10-21 21:29:21.465 TerrainRendering[11293:fb03] Tiles:7316200  Disgusting pointer math:73165c0
2011-10-21 21:29:21.465 TerrainRendering[11293:fb03] Tiles:7316200  Disgusting pointer math:7316200
2011-10-21 21:29:21.466 TerrainRendering[11293:fb03] Tiles:7316200  Disgusting pointer math:73164d0
2011-10-21 21:29:21.467 TerrainRendering[11293:fb03] Tiles:7316200  Disgusting pointer math:73167a0
2011-10-21 21:29:21.470 TerrainRendering[11293:fb03] Tiles:7316200  Disgusting pointer math:7316a70
2011-10-21 21:29:21.470 TerrainRendering[11293:fb03] Tiles:7316200  Disgusting pointer math:7316d40

1 个答案:

答案 0 :(得分:0)

您在memcpy中的偏移量应为(i*MAX_HEIGHT + j)。您希望使用“i”(外部循环)跳转行,并使用“j”(内部循环)顺序钻取它们。

希望这有帮助