Question

我正在使用四个表：

class Product(models.Model):
    active = models.BooleanField(default=True)
    name = models.CharField(max_length=40, unique=True)
    acronym = models.CharField(max_length=3, unique=True)

class Alarm(models.Model):
    active = models.BooleanField(default=True)
    product = models.ForeignKey(Product) #NEW
    name = models.CharField(unique=True, max_length=35)
    image_file = models.CharField(max_length=30)

class File(models.Model):
    reference = models.CharField(max_length=40)
    product = models.ForeignKey(Product, related_name='item_product') #NEW
    created = models.DateTimeField(default=datetime.now)
    created_by = models.ForeignKey(User)

class FileAlarm(models.Model):
    file = models.ForeignKey(File)
    created = models.DateTimeField()
    created_by = models.ForeignKey(User, related_name="alarm_created_by")
    alarm_date = models.DateField(default=datetime.now)
    alarm_type = models.ForeignKey(Alarm)
    alarm_comment = models.CharField(max_length=80, blank=True, null=True)

不幸的是，我需要将onChange事件传递给FileAlarm.alarm_type的表单元素（这意味着queryset中的__init__无效）所以我需要填充{ {1}}变量choices=。我只是想知道如何做到这一点，因为我只想要ChoiceField的警报并且链接到与active链接的product相同的File。 / p>

FileAlarm

Answer 1

事实证明最好的方法是：

class FileAlarmForm(ModelForm):

    def __init__(self,file,*args,**kwargs):
        super(FileAlarmForm, self).__init__(*args, **kwargs)
        p = Product.objects.get(id=file.product_id)
        self.fields['alarm_type'].widget = Select(attrs={'onchange':'updateAlarmImage'})
        self.fields['alarm_type'].queryset = Alarm.objects.filter(product=p)

Django填充选择字段

1 个答案: