实现JS脚本来提取/解析XML提要并将内容返回到html。不幸的是,它似乎没有这样做,因为页面上只显示div标签之间的文本(Feed!)。
function loadRSSFeed(param){
var xmlhttp = new XMLHttpRequest();
xmlhttp.open("GET",'http://feeds.feedburner.com/engadget/Dnjv',false);
xmlhttp.send();
xmlDoc = xmlhttp.responseXML;
var strBuffer= "";
strBuffer = strBuffer +"<table border='1'>";
var x=xmlDoc.getElementsByTagName("item");
for (i=0;i<x.length;i++){
strBuffer = strBuffer +"<tr><td><a href='";
strBuffer = strBuffer +(x[i].getElementsByTagName("link")[0].childNodes[0].nodeValue);
strBuffer = strBuffer +"'>";
strBuffer = strBuffer +(x[i].getElementsByTagName("title")[0].childNodes[0].nodeValue);
strBuffer = strBuffer +"</a></td></tr><tr><td>";
strBuffer = strBuffer +(x[i].getElementsByTagName("description")[0].childNodes[0].nodeValue.substring(0,180));
strBuffer = strBuffer + "<a href='";
strBuffer = strBuffer +(x[i].getElementsByTagName("link")[0].childNodes[0].nodeValue);
strBuffer = strBuffer +"'>... Read More...</a>";
strBuffer = strBuffer +"</td></tr>";
if(i==10){
break;
}
}
strBuffer = strBuffer +"</table>";
document.getElementById(param).innerHTML =strBuffer;
}
它是这样导入的(成功): 然后在身体中调用
<body onload ="loadRSSFeed('feeddisplay');">
<h1>All the news that's fit to render</h1>
<div id="feeddisplay">Feed!</div>
</body>
但它没有显示出来!页面的其余部分确实如此......
思想?
答案 0 :(得分:2)
不应该是XMLHttp * 请求 *?
答案 1 :(得分:1)
谷歌供稿阅读器api更强大,并且没有更多功能来处理rss
http://code.google.com/apis/feed/v1/
另外我认为onLoad可能无法找到div ...?你在加载div feed之后尝试执行脚本吗...只需要2美分。