我有一个带有一些属性的IAddress类。然后,我有一个实现此接口的具体类型。这个具体类型有几个我可以使用的不同构造函数。如何在运行时将参数值传递给其中一个构造函数?我不能使用配置文件,因为我将多次重复使用这个具体类型,每次参数值都不同。
IWindsorContainer container = new WindsorContainer(new XmlInterpreter());
IAddress address = container.Resolve<IAddress>();
public interface IAddress
{
string Address1 { get; set; }
string Address2 { get; set; }
string City { get; set; }
string State { get; set; }
string ZipCode { get; set; }
}
class TestAddress : IAddress
{
private string _address1;
private string _address2;
private string _city;
private string _countyName;
private string _state;
private string _zipCode;
public string Address1
{
get { return _address1; }
set { _address1 = value; }
}
public string Address2
{
get { return _address2; }
set { _address2 = value; }
}
public string City
{
get { return _city; }
set { _city = value; }
}
public string State
{
get { return _state; }
set { _state = value; }
}
public string ZipCode
{
get { return _zipCode; }
set { _zipCode = value; }
}
public string CountyName
{
get { return _countyName; }
set { _countyName = value; }
}
public MelissaAddress(string address1, string address2, string city, string state, string zipcode)
{
Address1 = address1;
Address2 = address2;
City = city;
State = state;
ZipCode = zipcode;
}
public MelissaAddress(string address1, string address2, string zipcode) : this(address1, address2, null, null, zipcode)
{ }
public MelissaAddress(string address1, string address2, string city, string state) : this(address1, address2, city, state, null)
{ }
}
答案 0 :(得分:23)
您可以使用Resolve(object argumentsAsAnonymousType)
或Resolve(IDictionary arguments)
。 Windsor将选择最佳匹配构造函数。
例如,这将选择第二个构造函数:
container.Resolve<IAddress>(
new {address1 = "myaddress1", address2 = "myaddress2", zipcode = "myzipcode"}
)