我已经阅读了这里的几篇文章,建议使用单例代码,我已阅读并放入音板,因为我想使用单例代码只允许一个媒体播放器实例,无论用户定义多少次点击。
基本上我只想要一个声音,如果用户在播放期间点击另一个按钮,它会停止当前声音并播放按下的声音。我只想要一个MediaPlayer实例,但不了解如何实现它。
以下是我的代码的基本概念:
package com.example.context;
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import android.app.Activity;
import android.content.ContentValues;
import android.content.Intent;
import android.media.MediaPlayer;
import android.net.Uri;
import android.os.Bundle;
import android.provider.MediaStore;
import android.view.ContextMenu;
import android.view.MenuItem;
import android.view.View;
import android.view.ContextMenu.ContextMenuInfo;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.Toast;
public class main extends Activity implements OnClickListener {
MediaPlayer player;
int[] ressound ={R.raw.boomstick, R.raw.chainsaw, R.raw.shebitch, R.raw.byebye,
R.raw.comegetsome, R.raw.groovy, R.raw.shoelace, R.raw.smart, R.raw.yeahbaby};//added as needed
int j=0;
private static final String TAG = "MyTag";
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
//Coding for all buttons, registers, and Listeners
Button btn1 = (Button) findViewById(R.id.btn1);
registerForContextMenu(btn1);
btn1.setOnClickListener(this);
Button btn2 = (Button) findViewById(R.id.btn2);
registerForContextMenu(btn2);
btn2.setOnClickListener(this);
Button btn3 = (Button) findViewById(R.id.btn3);
registerForContextMenu(btn3);
btn3.setOnClickListener(this);
}
//On click Handlers for multiple buttons
public void onClick(View v) {
switch(v.getId()){
case R.id.btn1:
// action to perform on button 1
j = 0;
playResource();
break;
case R.id.btn2:
// action to perform on button 1
j = 1;
playResource();
break;
case R.id.btn3:
// action to perform on button 1
j = 2;
playResource();
break;
}
public void playResource(int j, int resource) {
this.j = j;
if (player != null) {
if (player.isPlaying())
player.stop();
player.reset();
//from MediaPlayer implementation (link above)
try {
AssetFileDescriptor afd = getResources().openRawResourceFd(resource);
if (afd == null) return;
player.setDataSource(afd.getFileDescriptor(), afd.getStartOffset(), afd.getLength());
afd.close();
player.prepare();
} catch (IOException ex) {
Log.d(TAG, "create failed:", ex);
// failed: return
} catch (IllegalArgumentException ex) {
Log.d(TAG, "create failed:", ex);
// failed: return
} catch (SecurityException ex) {
Log.d(TAG, "create failed:", ex);
// failed: return
}
}
else {
//player is null
//it will create new MediaPlayer instance, setDataSource and call prepare
player = MediaPlayer.create(this, resource);
}
//if everything ok play file
//in case of any error return from method before (catch)
player.start();
}
这是我必须更新和更改我的代码,但它给我一个传递playresource()函数的问题。我是不是错了,如果它是私密的,那就过去了。
答案 0 :(得分:4)
你不需要单身人士。你在做什么是每次想要播放文件时调用create方法。这是错误的,因为你已经有了MediaPlayer实例。 检查MediaPlayer.create implementation。 我会这样做:
playResource方法示例:
private static final String TAG = "MyTag";
playResource(int j, int resource) {
this.j = j;
if (player != null) {
if (player.isPlaying())
player.stop();
player.reset();
//from MediaPlayer implementation (link above)
try {
AssetFileDescriptor afd = getResources().openRawResourceFd(resource);
if (afd == null) return null;
player.setDataSource(afd.getFileDescriptor(), afd.getStartOffset(), afd.getLength());
afd.close();
player.prepare();
} catch (IOException ex) {
Log.d(TAG, "create failed:", ex);
// failed: return
} catch (IllegalArgumentException ex) {
Log.d(TAG, "create failed:", ex);
// failed: return
} catch (SecurityException ex) {
Log.d(TAG, "create failed:", ex);
// failed: return
}
}
else {
//player is null
//it will create new MediaPlayer instance, setDataSource and call prepare
player = MediaPlayer.create(this, resource);
}
//if everything ok play file
//in case of any error return from method before (catch)
player.start();
}
如果您不再需要MediaPlayer,则应该将其发布。例如在onPause()调用中:
if (player != null) {
player.release();
player = null;
}
我没有测试过,所以可能会有错误。希望它有所帮助。
答案 1 :(得分:1)
getSingletonObject()方法应返回MediaPlayer的实例,使用MediaPlayer的默认构造函数创建(不指定资源)。
您可以从主类中的onCreate()调用getSingletonObject()并使用它初始化播放器。
稍后在onClick()中,你应该调用,player.prepare()然后调用player.setDataSource(),传入资源。
因此,您的代码应如下所示:
public static MediaPlayer getSingletonObject()
{
if (ref == null)
// it's ok, we can call this constructor
ref = new MediaPlayer();
return ref;
}
在主类中,在onCreate()方法中,
public void onCreate(Bundle savedInstanceState) {
//....
//....
player=SingletonObject.getSingletonObject();
}
希望你能自己弄清楚onClick()中的代码。并且不要忘记在onClick()方法中添加适当的try..catch子句。
希望这会有所帮助!!
答案 2 :(得分:0)
我一直在尝试为自己的项目解决这个问题。我遇到了同样的问题,即播放第二次播放时会让应用程序崩溃。
添加player = new MediaPlayer();
解决了这个问题(似乎没有在try-catch块中启动媒体播放器)。
请参阅以下代码:
playResource(int j, int resource) {
this.j = j;
if (player != null) {
if (player.isPlaying())
player.stop();
player.reset();
try {
player = new MediaPlayer(); //added to the code
AssetFileDescriptor afd = getResources().openRawResourceFd(resource);
if (afd == null) return null;
player.setDataSource(afd.getFileDescriptor(), afd.getStartOffset(), afd.getLength());
afd.close();
player.prepare();
} catch (IOException ex) {
Log.d(TAG, "create failed:", ex);
// failed: return
} catch (IllegalArgumentException ex) {
Log.d(TAG, "create failed:", ex);
// failed: return
} catch (SecurityException ex) {
Log.d(TAG, "create failed:", ex);
// failed: return
}
}
else {
//player is null
//it will create new MediaPlayer instance, setDataSource and call prepare
player = MediaPlayer.create(this, resource);
}