Question

-----------------------------------------------
Value     ISRepeat    Changed
------------------------------------------------
666-66-8888 NULL    2011-10-19 15:28:47.310
555-55-6666 NULL    2011-10-19 15:27:26.413
444-44-5555 NULL    2011-10-19 15:25:02.660
333-33-4444 NULL    2011-10-19 15:23:57.120
222-22-3333 NULL    2011-10-19 15:13:57.903
222-22-2222 NULL    2011-10-19 15:13:03.517
100-10-2222 NULL    2011-10-19 15:07:52.010
100-10-1111 NULL    2011-10-19 15:06:59.690

我有一张这样的桌子。我想打印值

555-55-6666 NULL    2011-10-19 15:27:26.413

这是基于TIME（更改列）的表格中的最后一行但是....条件是最近值之前的时间。我怎么能这样做？

Answer 1

最近的时间是：

SELECT MAX(Changed) AS most_recent FROM AnonymousTable

您希望最大时间小于此行：

SELECT MAX(Changed) AS second_latest
  FROM AnonymousTable
 WHERE Changed < (SELECT MAX(Changed) AS most_recent FROM AnonymousTable)

因此，您选择相关的行：

SELECT *
  FROM AnonymousTable
 WHERE Changed =
       (SELECT MAX(Changed) AS second_latest
          FROM AnonymousTable
         WHERE Changed < (SELECT MAX(Changed) AS most_recent FROM AnonymousTable)
       )

可能有一种更简洁的方法可以做到这一点，而且这种技术并不能很好地概括为第三或第四个最新值。 OLAP功能很可能有所帮助。

Answer 2

试试这个：

select top 1 *
from YourTable
where Changed not in
(
    select max(Changed)
    from YourTable
)
order by Changed desc

或者：

select *
from
(
    select ROW_NUMBER() over (order by Changed desc) as row_num,
        *
    from YourTable
) a
where row_num = 2

如何在T-SQL中打印最新但一行？

2 个答案: