Question

我有一个包含XYZ类的多个序列化对象的文件。序列化时，每个XYZ对象都附加到文件中。

现在我需要从文件中读取每个对象，并且我只能读取第一个对象。

知道如何从文件中读取每个对象并最终将其存储到List中吗？

Answer 1

尝试以下方法：

List<Object> results = new ArrayList<Object>();
FileInputStream fis = new FileInputStream("cool_file.tmp");
ObjectInputStream ois = new ObjectInputStream(fis);

try {
    while (true) {
        results.add(ois.readObject());
    }
} catch (OptionalDataException e) {
    if (!e.eof) 
        throw e;
} finally {
    ois.close();
}

跟进Tom的精彩评论，多个ObjectOutputStream的解决方案将是，

public static final String FILENAME = "cool_file.tmp";

public static void main(String[] args) throws IOException, ClassNotFoundException {
    String test = "This will work if the objects were written with a single ObjectOutputStream. " +
            "If several ObjectOutputStreams were used to write to the same file in succession, " +
            "it will not. – Tom Anderson 4 mins ago";

    FileOutputStream fos = null;
    try {
        fos = new FileOutputStream(FILENAME);
        for (String s : test.split("\\s+")) {
            ObjectOutputStream oos = new ObjectOutputStream(fos);
            oos.writeObject(s);
        }
    } finally {
        if (fos != null)
            fos.close();
    }

    List<Object> results = new ArrayList<Object>();

    FileInputStream fis = null;
    try {
        fis = new FileInputStream(FILENAME);
        while (true) {
            ObjectInputStream ois = new ObjectInputStream(fis);
            results.add(ois.readObject());
        }
    } catch (EOFException ignored) {
        // as expected
    } finally {
        if (fis != null)
            fis.close();
    }
    System.out.println("results = " + results);
}

Answer 2

您无法将ObjectOutputStreams附加到文件中。它们包含标题以及您编写的对象。修改你的技术。

您的EOF检测也是错误的。您应该单独捕获EOFException。 OptionalDataException意味着完全不同的东西。

Answer 3

这对我有用

  System.out.println("Nombre del archivo ?");
                  nArchivo= sc.next();
                  sc.nextLine();
                  arreglo=new ArrayList<SuperHeroe>();

                  try{

                         FileInputStream fileIn = new FileInputStream(nArchivo);
                         ObjectInputStream in = new ObjectInputStream(fileIn);

                        while(true){
                            arreglo.add((SuperHeroe) in.readObject());

                        }



                    }

                      catch(IOException i)
                      {
                         System.out.println("no hay mas elementos\n elementos cargados desde el archivo:" );

                         for(int w=0;w<arreglo.size();w++){
                          System.out.println(arreglo.get(w).toString());
                         }



                      }catch(ClassNotFoundException c)
                      {
                         System.out.println("No encontre la clase Estudiante !");
                         c.printStackTrace();

                         return;
                      }

Answer 4

您可以按照下面提到的代码以不同的方式处理文件结尾：

public static void main(String[] args) throws FileNotFoundException, IOException, ClassNotFoundException {
    // TODO Auto-generated method stub

    ObjectOutputStream oos = new ObjectOutputStream(new FileOutputStream("E://sample.txt"));
    oos.writeObject(new Integer(5));
    oos.writeObject(new Integer(6));
    oos.writeObject(new Integer(7));
    oos.writeObject(new Integer(8));
    oos.flush();
    oos.close();

    ObjectInputStream ios = new ObjectInputStream(new FileInputStream("E://sample.txt"));
    Integer temp;
    try {
        while ((temp = (Integer) ios.readObject()) != null) {
            System.out.println(temp);
        }
    } catch (EOFException e) {

    } finally {
        ios.close();
    }

}

它将从文件中写入和读取多个整数对象，而不会抛出任何异常。

在Java中反序列化文件中的对象

4 个答案: