如何根据创建的时间戳将两个最接近的行组合成一行

Question

我有以下sql 2008表。

ID  RefundId    RefundStatusId          CreatedOn
334 549         3                   2011-10-12 12:04:37.773
333 549         1                   2011-10-12 12:04:20.390
332 549         6                   2011-10-12 12:03:05.990

任何查询都可以给我一个结果：

RefundCheckId   StatusId             PreviousStatusId           CreatedOn
    549             3                    1                        2011-10-12 12:04:37.773
    549             1                    6                        2011-10-12 12:04:20.390
    549             6                    null                     2011-10-12 12:03:05.990

以下解决方案：根据Marco的回答进行了更新。

SELECT t.RefundId AS RefundCheckId, t.RefundStatusId AS StatusId,
  (SELECT TOP 1 RefundStatusId FROM table
   WHERE RefundId = t.RefundId AND CreatedOn < t.CreatedOn
   ORDER BY CreatedOn DESC) AS PreviousStatusId, t.CreatedOn
FROM table t
WHERE t.RefundId = 549
ORDER BY t.CreatedOn DESC

Answer 1

尝试

MySql版本

SELECT t.RefundId AS RefundCheckId, t.RefundStatusId AS StatusId,
  (SELECT RefundStatusId FROM your_table 
   WHERE ID < t.ID
   ORDER BY ID DESC
   LIMIT 1) AS PreviousStatusId, t.CreatedOn
FROM your_table t
ORDER BY t.ID DESC

MS-SQL版本

SELECT t.RefundId AS RefundCheckId, t.RefundStatusId AS StatusId,
  (SELECT TOP 1 RefundStatusId FROM your_table 
   WHERE ID < t.ID
   ORDER BY ID DESC) AS PreviousStatusId, t.CreatedOn
FROM your_table t
ORDER BY t.ID DESC