Question

如何在结构中创建节点数组。我上传了我的样本。

 struct timebasedSpecificTimesIntervalNode
 {
   int hrs;
   int min;
   int sec;
 };

 struct timebasedSpecificTimesInterval
 {
     struct timebasedSpecificTimesIntervalNode* nodes;
     int count;
     char *cFilePath;
 };

如何为此结构创建节点数组timebasedSpecificTimesInterval。

  struct timebasedSpecificTimesInterval specificTimes;

如何为此结构创建3个节点的数组。

修改

为此值创建结构

  hrs:5,2,3 min 23,58,4 sec 54,12,2

Thnks

Answer 1

int main(void) {
    struct timebasedSpecificTimesInterval data;
    data.count = 3;
    data.nodes = malloc(data.count * sizeof *data.nodes);
    data.cFilePath = NULL;
    if (data.nodes) {

        data.nodes[0].hrs = 5; data.nodes[0].min = 23; data.nodes[0].sec = 54;
        data.nodes[1].hrs = 2; data.nodes[1].min = 58; data.nodes[1].sec = 12;
        data.nodes[2].hrs = 3; data.nodes[2].min = 4;  data.nodes[2].sec = 2;
        /* use data */

        free(data.nodes);
        data.nodes = NULL; /* optional */
        data.count = 0;
    }
    return 0;
}

编辑：使用OP中提供的示例

Answer 2

我就是这样做的。除非我有完全错误的结束。我不喜欢乱丢我代码的新struct关键字。

typedef struct 
 {
   int hrs;
   int min;
   int sec;
 } timebasedSpecificTimesIntervalNode;

 typedef struct 
 {
     timebasedSpecificTimesIntervalNode* nodes;
     int count;
     char *cFilePath;
 } timebasedSpecificTimesInterval;

int main (void)
{
  timebasedSpecificTimesIntervalNode nodeArray[3];  
  timebasedSpecificTimesInterval specificTimesInterval;

  //initialise the pointer
  specificTimesInterval.nodes = nodeArray;

  // you can now access the pointer as an array
  nodeArray[0].hrs = 3; //arbitrary value

}

Answer 3

除非我误解了这个问题......就像你对任何其他阵列一样：

struct timebasedSpecificTimesInterval specificTimes[3];

嵌套结构问题

3 个答案: