我想要检索存在于数据库中的图像,图像标签iam在标签中给出,这就是为什么我没有得到我将如何做 这是我的aspx代码
<div id="mask-gallery">
<ul id="gallery" runat="server">
<li>
<img src="/images/projects/<%# Eval("Top_Image")%>" width="981" height="279" title="hello" alt="hello"/></li>
<asp:Image ID="imgTop" ImageUrl='/images/Projects/<%# Eval("Top_Image") %>' runat="server" width="981" height="279" AlternateText="hello" />
</ul>
</div>
这里是我的cs代码
SqlConnection con = new SqlConnection(System.Configuration.ConfigurationManager.AppSettings["Constr"]);
protected void Page_Load(object sender, EventArgs e)
{
if (!IsPostBack)
{
GetImageData();
}
}
protected void GetImageData()
{
SqlParameter[] param = new SqlParameter[1];
param[0] = new SqlParameter("@Id_Project", SqlDbType.VarChar, 300);
param[0].Value = lblid.Text.ToString().Trim();
SqlCommand Cmdd = new SqlCommand("tpRetrieve_Project_Master_Top_Image", con);
Cmdd.CommandType = CommandType.StoredProcedure;
Cmdd.Parameters.Add(param[0]);
con.Open();
SqlDataReader drr = Cmdd.ExecuteReader();
if (drr.HasRows)
{
while (drr.Read())
{
hd_Show_In_Top.Value = drr["Show_In_Top"].ToString().Trim();
if (hd_Show_In_Top.Value == "Yes")
{
hd_thumbnail.Value = drr["Top_Image"].ToString().Trim();
lblbdescription.Text = drr["Description"].ToString().Trim();
lblbprojecttype.Text = drr["Project_type"].ToString().Trim();
// lblrotation.Text = lblrotation.Text + "<a href='/about-us/people.aspx'><img class='cloudcarousel' src='/images/AboutUsTopImages/" + hd_thumbnail..Value.ToString().Trim() + " '/></a>";
}
}
}
drr.Close();
con.Close();
}
答案 0 :(得分:2)
一种可能的(实际上非常常见的)方法是创建一个HttpHandler,它将从数据库中获取图像并将其写入响应。查看this link以查看有效示例。
答案 1 :(得分:0)
如果您将图像名称与扩展名一起存储在数据库中,则可以执行此类操作
var x = datasource();//your datasource which contains the imagefile
<img src='" + Page.ResolveUrl("~/images/projects/") + x.imageFile + "' alt='Test' />
答案 2 :(得分:0)
如果Top_Image
包含filename.ext(sample.jpeg
),那么你应该试试这个,
<img runat="server"
src='<%# Eval("Top_Image","~/images/projects/{0}") %>'
width="981"
height="279"
title="hello"
alt="hello"/>
</li>
<asp:Image ID="imgTop"
ImageUrl='<%# Eval("Top_Image","~/images/Projects/{0}") %>'
runat="server"
width="981"
height="279"
AlternateText="hello" />
如果您没有绑定DataSource,则无需使用Eval()
方法。您可以在后面的代码中指定ImageUrl属性。
if (drr.Read())
{
hd_Show_In_Top.Value = drr["Show_In_Top"].ToString().Trim();
if (hd_Show_In_Top.Value == "Yes")
{
imgTop.ImageUrl="~/images/Projects/" +drr["Top_Image"].ToString().Trim();
....
}
}