Question

可能重复：
Combining several database table together?

我希望从两个数据库表得到这样的输出：

伊斯坦布尔的一周之旅_1 88888＆amp; 99999 $ 112233 $ 445566 |三晚两天| 15:29
  伊斯坦布尔2周的一周之旅55555＆amp; 66666 $ 77777 |三晚两天| 12:03
  伊斯坦布尔3周的一周之旅11111＆amp; 22222 $ 33333 $ 44444 |三晚两天| 12:03

这些是我的表格：

enter image description here

更新

它给了我这个输出：http://img708.imageshack.us/img708/2404/outputnz.gif但是如果我输入$ find值“55555”，输出为：http://img528.imageshack.us/img528/3576/outputnow.gif但我想要的是：http://img832.imageshack.us/img832/120/outputwant.gif。怎么回事？

$query = $this -> db -> query('
    SELECT
       @rownum := @rownum + 1 rownum,
       tour_foreign.id, 
       tour_foreign.name, 
       MIN(tour_foreign_residence.name_re) AS name_re, 
       tour_foreign.service, 
       tour_foreign.date_go, 
       tour_foreign.date_back, 
       tour_foreign.term,
       tour_foreign.useradmin_submit,
       tour_foreign.date_submit,
       GROUP_CONCAT( tour_foreign_residence.name_re 
                     ORDER BY tour_foreign_residence.name_re 
                     SEPARATOR " $ "
                   ) AS name_re_all
    FROM   tour_foreign 
      INNER JOIN tour_foreign_residence 
        ON ( tour_foreign.id = tour_foreign_residence.relation )
      JOIN (SELECT @rownum := 0) r
    WHERE  tour_foreign.name LIKE "%' . $find . '%" 
        OR tour_foreign_residence.name_re_all LIKE "%' . $find . '%"
    GROUP BY  tour_foreign.id ');

我从sql上面得到以下错误：

发生数据库错误
错误编号：1054


'where'中的未知列'tour_foreign_residence.name_re_all'   条款“


SELECT @rownum：= @rownum + 1 rownum，tour_foreign.id，   tour_foreign.name，MIN（tour_foreign_residence.name_re）AS name_re，   tour_foreign.service，tour_foreign.date_go，tour_foreign.date_back，   tour_foreign.term，tour_foreign.useradmin_submit，   tour_foreign.date_submit，GROUP_CONCAT（tour_foreign_residence.name_re   订购者：tour_foreign_residence.name_re分隔符“$”）AS   name_re_all FROM tour_foreign INNER JOIN tour_foreign_residence ON（   tour_foreign.id = tour_foreign_residence.relation）加入（选择   @rownum：= 0）r WHERE tour_foreign.name LIKE“%%”OR   tour_foreign_residence.name_re_all LIKE“%%”GROUP BY   tour_foreign.id


文件名：   d：\ XAMPP \ htdocs中\ SYSTEM \数据库\ DB_driver.php


行号：330

Answer 1

您需要按某种方式进行分组，或者聚合GROUP_CONCAT()会将所有行合并为一个：

GROUP BY  tour_foreign.id

使用：

$query = $this -> db -> query('
    SELECT
       @rownum := @rownum + 1 rownum,
       tour_foreign.id, 
       tour_foreign.name, 
       MIN(tour_foreign_residence.name_re) AS name_re, 
       tour_foreign.service, 
       tour_foreign.date_go, 
       tour_foreign.date_back, 
       tour_foreign.term,
       tour_foreign.useradmin_submit,
       tour_foreign.date_submit,
       GROUP_CONCAT( tour_foreign_residence.name_re 
                     ORDER BY tour_foreign_residence.name_re 
                     SEPARATOR " $ "
                   ) AS name_re_all
    FROM   tour_foreign 
      INNER JOIN tour_foreign_residence 
        ON ( tour_foreign.id = tour_foreign_residence.relation )
      JOIN (SELECT @rownum := 0) r
    WHERE  tour_foreign.name LIKE "%' . $find . '%" 
        OR tour_foreign_residence.name_re LIKE "%' . $find . '%"
    GROUP BY  tour_foreign.id ');

Answer 2

尝试在SQL语句的末尾添加GROUP BY子句。

Answer 3

SELECT a.name, GROUP_CONCAT(b.name_re ORDER BY b.name_re SEPARATOR " & "), a.term, a.time_go 
FROM tour_foreign a INNER JOIN tour_foreign residence b
ON a.id = b.relation
GROUP BY a.name

我只是在学习SQL，所以我把你的问题当作练习。希望它有效。

将两个表与sql JOIN结合起来？

3 个答案: