所有
我正在将JPA用于此应用程序和Mapping实体的注释。我有一个名为UserStory的实体和另一个名为Revision的实体。 UserStory to Revision有一个OneToMany。
@Entity
@Table(name = "user_story")
@NamedNativeQueries({
@NamedNativeQuery(name = "storyBacklog", query = "SELECT userstory.rank AS rank, userstory.description AS description, userstory.estimate AS estimate, userstory.name AS name, "
+ "userstory.id AS id, userstory.status AS status FROM user_story userstory ORDER BY userstory.rank ASC", resultClass = UserStory.class),
@NamedNativeQuery(name = "getCos", query = "SELECT conditions.cos As cos FROM story_cos conditions WHERE conditions.story_id=?1", resultSetMapping = "cosMapping") })
@SqlResultSetMappings({ @SqlResultSetMapping(name = "cosMapping", columns = @ColumnResult(name = "cos")) })
public class UserStory implements Serializable {
private static final long serialVersionUID = 248298400283358441L;
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
...
@OneToMany(cascade = CascadeType.ALL)
@JoinTable(name = "story_revisions", joinColumns = @JoinColumn(name = "story_id"), inverseJoinColumns = @JoinColumn(name = "revision_id"))
private Set<Revision> revisions;
这是修订实体:
@Entity
@Table(name = "revision")
public class Revision implements Serializable {
private static final long serialVersionUID = -1823230375873326645L;
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
@Column(nullable = false)
private String description;
@Column(name = "date_created", nullable = false)
@Temporal(TemporalType.TIMESTAMP)
private Date creationDate;
当我创建userStory时;我在其上添加了一个修订版,
但是除非我首先坚持故事,否则不会填充连接表 然后添加修订并合并它。
这是保存UserStory的代码:
public UserStory saveUserStory(UserStory userStory) {
Revision revision = new Revision();
revision.setCreationDate(new Timestamp(System.currentTimeMillis()));
revision.setDescription("User story created");
Set<Revision> revisions = new HashSet<Revision>();
revisions.add(revision);
userStory.setRevisions(revisions);
return storyDao.create(userStory);
}
在StoryDao中我调用了persist方法:
@Transactional(readOnly = false)
public UserStory create(UserStory userStory) {
if (userStory.getRank() == null) {
Integer highestRank = 0;
highestRank = (Integer) entityManager.createNativeQuery("select max(rank) from user_story")
.getSingleResult();
if (highestRank != null)
highestRank += 1;
else
highestRank = new Integer(1);
userStory.setRank(highestRank);
}
entityManager.persist(userStory);
LOGGER.debug("Added User Story with id " + userStory.getId());
entityManager.detach(userStory);
return userStory;
}
这是来自LOGS的SQL
Hibernate:
insert
into
user_story
(description, estimate, name, rank, status)
values
(?, ?, ?, ?, ?)
Hibernate:
insert
into
revision
(date_created, description)
values
(?, ?)
Hibernate:
select
revision0_.id as id5_0_,
revision0_.date_created as date2_5_0_,
revision0_.description as descript3_5_0_
from
revision revision0_
where
revision0_.id=?
Hibernate:
select
userstory0_.id as id3_1_,
userstory0_.description as descript2_3_1_,
userstory0_.estimate as estimate3_1_,
userstory0_.name as name3_1_,
userstory0_.rank as rank3_1_,
userstory0_.status as status3_1_,
revisions1_.story_id as story1_3_3_,
revision2_.id as revision2_3_,
revision2_.id as id5_0_,
revision2_.date_created as date2_5_0_,
revision2_.description as descript3_5_0_
from
user_story userstory0_
left outer join
story_revisions revisions1_
on userstory0_.id=revisions1_.story_id
left outer join
revision revision2_
on revisions1_.revision_id=revision2_.id
where
userstory0_.id=?
我可以从这里看到它保存用户故事和修订版,但是然后在插入连接表之前尝试运行连接以查看关系是否存在。当然它找不到,因为我正在创建这个对象。
在这种情况下如何填充连接表?
答案 0 :(得分:0)
立即行动。这是更新的代码
revisions.add(revision);
userStory = storyDao.create(userStory);
userStory.setRevisions(revisions);
return storyDao.update(userStory);
我仍然不确定为什么要这样做;我坚持一个对象然后更新它的两步法。