UniqueIdentifiers的问题
我们有一个现有的数据库，它广泛地使用uniqueidentifiers（不幸的是！）作为主键和一些表的一些可空列。我们遇到了这样一种情况，即在这些表上运行的某些报告会对这些uniqueidentifier进行排序，因为表中没有其他列可以进行有意义的排序（这并不具有讽刺性！）。目的是排序，以便按照插入顺序显示项目，但不使用NewSequentialId（）插入它们 - 因此浪费时间。
关于排序算法的事实
无论如何，考虑到SQL Server根据从结束的第5个字节组（6个字节）开始的字节组对uniqueidentifier进行排序，并向第1个字节组（4个字节）移动，从而颠倒第3个字节组（2个字节）的顺序从左到右，
我的问题
我很想知道是否有任何现实生活情况，这种情况有点帮助。
SQL Server如何在内部存储uniqueidentifier，这可能会提供洞察力 为什么它有这种糟糕的排序算法？
参考：
Alberto Ferrari's discovery of the SQL Server GUID sort
示例
在具有以下数据的uniqueidentifier列上使用Order By时，Uniqueidentifier的排序如下所示。
请注意，以下数据按升序排序，最高排序首选项是从第5个字节组到第1个字节组（向后）。
-- 1st byte group of 4 bytes sorted in the reverse (left-to-right) order below --
01000000-0000-0000-0000-000000000000
10000000-0000-0000-0000-000000000000
00010000-0000-0000-0000-000000000000
00100000-0000-0000-0000-000000000000
00000100-0000-0000-0000-000000000000
00001000-0000-0000-0000-000000000000
00000001-0000-0000-0000-000000000000
00000010-0000-0000-0000-000000000000
-- 2nd byte group of 2 bytes sorted in the reverse (left-to-right) order below --
00000000-0100-0000-0000-000000000000
00000000-1000-0000-0000-000000000000
00000000-0001-0000-0000-000000000000
00000000-0010-0000-0000-000000000000
-- 3rd byte group of 2 bytes sorted in the reverse (left-to-right) order below --
00000000-0000-0100-0000-000000000000
00000000-0000-1000-0000-000000000000
00000000-0000-0001-0000-000000000000
00000000-0000-0010-0000-000000000000
-- 4th byte group of 2 bytes sorted in the straight (right-to-left) order below --
00000000-0000-0000-0001-000000000000
00000000-0000-0000-0010-000000000000
00000000-0000-0000-0100-000000000000
00000000-0000-0000-1000-000000000000
-- 5th byte group of 6 bytes sorted in the straight (right-to-left) order below --
00000000-0000-0000-0000-000000000001
00000000-0000-0000-0000-000000000010
00000000-0000-0000-0000-000000000100
00000000-0000-0000-0000-000000001000
00000000-0000-0000-0000-000000010000
00000000-0000-0000-0000-000000100000
00000000-0000-0000-0000-000001000000
00000000-0000-0000-0000-000010000000
00000000-0000-0000-0000-000100000000
00000000-0000-0000-0000-001000000000
00000000-0000-0000-0000-010000000000
00000000-0000-0000-0000-100000000000
代码：
Alberto的代码扩展为表示排序是在字节上而不是在各个位上。
With Test_UIDs As (-- 0 1 2 3 4 5 6 7 8 9 A B C D E F
Select ID = 1, UID = cast ('00000000-0000-0000-0000-100000000000' as uniqueidentifier)
Union Select ID = 2, UID = cast ('00000000-0000-0000-0000-010000000000' as uniqueidentifier)
Union Select ID = 3, UID = cast ('00000000-0000-0000-0000-001000000000' as uniqueidentifier)
Union Select ID = 4, UID = cast ('00000000-0000-0000-0000-000100000000' as uniqueidentifier)
Union Select ID = 5, UID = cast ('00000000-0000-0000-0000-000010000000' as uniqueidentifier)
Union Select ID = 6, UID = cast ('00000000-0000-0000-0000-000001000000' as uniqueidentifier)
Union Select ID = 7, UID = cast ('00000000-0000-0000-0000-000000100000' as uniqueidentifier)
Union Select ID = 8, UID = cast ('00000000-0000-0000-0000-000000010000' as uniqueidentifier)
Union Select ID = 9, UID = cast ('00000000-0000-0000-0000-000000001000' as uniqueidentifier)
Union Select ID = 10, UID = cast ('00000000-0000-0000-0000-000000000100' as uniqueidentifier)
Union Select ID = 11, UID = cast ('00000000-0000-0000-0000-000000000010' as uniqueidentifier)
Union Select ID = 12, UID = cast ('00000000-0000-0000-0000-000000000001' as uniqueidentifier)
Union Select ID = 13, UID = cast ('00000000-0000-0000-0001-000000000000' as uniqueidentifier)
Union Select ID = 14, UID = cast ('00000000-0000-0000-0010-000000000000' as uniqueidentifier)
Union Select ID = 15, UID = cast ('00000000-0000-0000-0100-000000000000' as uniqueidentifier)
Union Select ID = 16, UID = cast ('00000000-0000-0000-1000-000000000000' as uniqueidentifier)
Union Select ID = 17, UID = cast ('00000000-0000-0001-0000-000000000000' as uniqueidentifier)
Union Select ID = 18, UID = cast ('00000000-0000-0010-0000-000000000000' as uniqueidentifier)
Union Select ID = 19, UID = cast ('00000000-0000-0100-0000-000000000000' as uniqueidentifier)
Union Select ID = 20, UID = cast ('00000000-0000-1000-0000-000000000000' as uniqueidentifier)
Union Select ID = 21, UID = cast ('00000000-0001-0000-0000-000000000000' as uniqueidentifier)
Union Select ID = 22, UID = cast ('00000000-0010-0000-0000-000000000000' as uniqueidentifier)
Union Select ID = 23, UID = cast ('00000000-0100-0000-0000-000000000000' as uniqueidentifier)
Union Select ID = 24, UID = cast ('00000000-1000-0000-0000-000000000000' as uniqueidentifier)
Union Select ID = 25, UID = cast ('00000001-0000-0000-0000-000000000000' as uniqueidentifier)
Union Select ID = 26, UID = cast ('00000010-0000-0000-0000-000000000000' as uniqueidentifier)
Union Select ID = 27, UID = cast ('00000100-0000-0000-0000-000000000000' as uniqueidentifier)
Union Select ID = 28, UID = cast ('00001000-0000-0000-0000-000000000000' as uniqueidentifier)
Union Select ID = 29, UID = cast ('00010000-0000-0000-0000-000000000000' as uniqueidentifier)
Union Select ID = 30, UID = cast ('00100000-0000-0000-0000-000000000000' as uniqueidentifier)
Union Select ID = 31, UID = cast ('01000000-0000-0000-0000-000000000000' as uniqueidentifier)
Union Select ID = 32, UID = cast ('10000000-0000-0000-0000-000000000000' as uniqueidentifier)
)
Select * From Test_UIDs Order By UID, ID
答案 0 :(得分：30)
此算法由SQL Server人员记录在此：How are GUIDs compared in SQL Server 2005?
另外，排序遵循字节组字节顺序（参见此处：Globally unique identifier）。组10-15和8-9存储为大端（对应于维基百科文章中的Data4），因此它们被比较为大端。使用little endian比较其他组。
答案 1 :(得分：3)
Necromancing。
对于那些发现接受的答案有点模糊的人来说，这是一项特殊的服务
代码说明了自己，神奇的部分是
System.Guid g
g.ToByteArray();
int[] m_byteOrder = new int[16] // 16 Bytes = 128 Bit
{10, 11, 12, 13, 14, 15, 8, 9, 6, 7, 4, 5, 0, 1, 2, 3};
public int Compare(Guid x, Guid y)
{
byte byte1, byte2;
//Swap to the correct order to be compared
for (int i = 0; i < NUM_BYTES_IN_GUID; i++)
{
byte1 = x.ToByteArray()[m_byteOrder[i]];
byte2 = y.ToByteArray()[m_byteOrder[i]];
if (byte1 != byte2)
return (byte1 < byte2) ? (int)EComparison.LT : (int)EComparison.GT;
} // Next i
return (int)EComparison.EQ;
}
完整代码：
namespace BlueMine.Data
{
public class SqlGuid
: System.IComparable
, System.IComparable<SqlGuid>
, System.Collections.Generic.IComparer<SqlGuid>
, System.IEquatable<SqlGuid>
{
private const int NUM_BYTES_IN_GUID = 16;
// Comparison orders.
private static readonly int[] m_byteOrder = new int[16] // 16 Bytes = 128 Bit
{10, 11, 12, 13, 14, 15, 8, 9, 6, 7, 4, 5, 0, 1, 2, 3};
private byte[] m_bytes; // the SqlGuid is null if m_value is null
public SqlGuid(byte[] guidBytes)
{
if (guidBytes == null || guidBytes.Length != NUM_BYTES_IN_GUID)
throw new System.ArgumentException("Invalid array size");
m_bytes = new byte[NUM_BYTES_IN_GUID];
guidBytes.CopyTo(m_bytes, 0);
}
public SqlGuid(System.Guid g)
{
m_bytes = g.ToByteArray();
}
public byte[] ToByteArray()
{
byte[] ret = new byte[NUM_BYTES_IN_GUID];
m_bytes.CopyTo(ret, 0);
return ret;
}
int CompareTo(object obj)
{
if (obj == null)
return 1; // https://msdn.microsoft.com/en-us/library/system.icomparable.compareto(v=vs.110).aspx
System.Type t = obj.GetType();
if (object.ReferenceEquals(t, typeof(System.DBNull)))
return 1;
if (object.ReferenceEquals(t, typeof(SqlGuid)))
{
SqlGuid ui = (SqlGuid)obj;
return this.Compare(this, ui);
} // End if (object.ReferenceEquals(t, typeof(UInt128)))
return 1;
} // End Function CompareTo(object obj)
int System.IComparable.CompareTo(object obj)
{
return this.CompareTo(obj);
}
int CompareTo(SqlGuid other)
{
return this.Compare(this, other);
}
int System.IComparable<SqlGuid>.CompareTo(SqlGuid other)
{
return this.Compare(this, other);
}
enum EComparison : int
{
LT = -1, // itemA precedes itemB in the sort order.
EQ = 0, // itemA occurs in the same position as itemB in the sort order.
GT = 1 // itemA follows itemB in the sort order.
}
public int Compare(SqlGuid x, SqlGuid y)
{
byte byte1, byte2;
//Swap to the correct order to be compared
for (int i = 0; i < NUM_BYTES_IN_GUID; i++)
{
byte1 = x.m_bytes[m_byteOrder[i]];
byte2 = y.m_bytes[m_byteOrder[i]];
if (byte1 != byte2)
return (byte1 < byte2) ? (int)EComparison.LT : (int)EComparison.GT;
} // Next i
return (int)EComparison.EQ;
}
int System.Collections.Generic.IComparer<SqlGuid>.Compare(SqlGuid x, SqlGuid y)
{
return this.Compare(x, y);
}
public bool Equals(SqlGuid other)
{
return Compare(this, other) == 0;
}
bool System.IEquatable<SqlGuid>.Equals(SqlGuid other)
{
return this.Equals(other);
}
}
}
答案 2 :(得分：0)
这是另一种方法。 GUID只是简单地改组即可进行正常的字符串比较，就像在SQL Server中发生的那样。这是Javascript，但是很容易转换成任何语言。
function guidForComparison(guid) {
/*
character positions:
11111111112222222222333333
012345678901234567890123456789012345
00000000-0000-0000-0000-000000000000
byte positions:
111111111111
00112233 4455 6677 8899 001122334455
*/
return guid.substr(24, 12) +
guid.substr(19, 4) +
guid.substr(16, 2) +
guid.substr(14, 2) +
guid.substr(11, 2) +
guid.substr(9, 2) +
guid.substr(6, 2) +
guid.substr(4, 2) +
guid.substr(2, 2) +
guid.substr(0, 2);
};