我有一个(动态)数组,在这个例子中包含4组数据(每组5个字段),但它可能只有一组或最多25组。
Array ( [lightwattage1] => 50 [lightvoltage1] => 12 [lightquantity1] => 2 [lightusage1] => 4 [lightcomment1] => [lightwattage2] => 60 [lightvoltage2] => 24 [lightquantity2] => 4 [lightusage2] => 5 [lightcomment2] => [lightwattage3] => 30 [lightvoltage3] => 240 [lightquantity3] => 4 [lightusage3] => 2 [lightcomment3] => [lightwattage4] => 25 [lightvoltage4] => 12 [lightquantity4] => 2 [lightusage4] => 6 [lightcomment4] => )
我想变成像
这样的东西Array ( Array ( [lightwattage1] => 50 [lightvoltage1] => 12 [lightquantity1] => 2 [lightusage1] => 4 [lightcomment1] => ),
Array ( [lightwattage2] => 60 [lightvoltage2] => 24 [lightquantity2] => 4 [lightusage2] => 5 [lightcomment2] => ),
Array ( [lightwattage3] => 30 [lightvoltage3] => 240 [lightquantity3] => 4 [lightusage3] => 2 [lightcomment3] => ),
Array ( [lightwattage4] => 25 [lightvoltage4] => 12 [lightquantity4] => 2 [lightusage4] => 6 [lightcomment4] => )
)
以这种方式创建原始数组:
$light = Array();
foreach( $_POST as $key => $val )
{
//field names that start with light to go in this array
if (strpos($key, 'light') === 0) {
$light[$key] = $val;
}
}
字段名称数字已经在表单提交之前添加了JS,而不是通过php脚本添加。 任何提示非常赞赏。
答案 0 :(得分:2)
这不是你问题的确切答案,但是......
您可以在POST
变量中使用数组,如下所示:
<input name="light[1][wattage]" />
<input name="light[1][voltage]" />
<input name="light[2][wattage]" />
<input name="light[2][voltage]" />
会给你:
$_POST['light'] == array(
1 => array(
'wattage' => '...',
'voltage' => '...',
),
2 => array(
'wattage' => '...',
'voltage' => '...',
),
)
答案 1 :(得分:1)
试试这个:
$prefixes = array();
$postfixes = array();
foreach($original_array as $key=>$value)
{
preg_match('/^([^\d]*)(\d+)$/',$key,$matches);
if(count($matches)>1)
{
if(!in_array($matches[1], $prefixes)) $prefixes[] = $matches[1];
if(!in_array($matches[2], $postfixes)) $postfixes[] = $matches[2];
}
}
$new_array = array();
foreach($postfixes as $postfix)
{
$new_element = array();
foreach($prefixes as $prefix)
{
if(isset($original_array[$prefix.$postfix])) $new_element[$prefix.$postfix] = $original_array[$prefix.$postfix];
}
$new_array[] = $new_element;
}
给定$ original_array等于描述,将产生$ new_array:
Array
(
[0] => Array
(
[lightwattage1] => 50
[lightvoltage1] => 12
[lightquantity1] => 2
[lightusage1] => 4
[lightcomment1] =>
)
[1] => Array
(
[lightwattage2] => 60
[lightvoltage2] => 24
[lightquantity2] => 4
[lightusage2] => 5
[lightcomment2] =>
)
[2] => Array
(
[lightwattage3] => 30
[lightvoltage3] => 240
[lightquantity3] => 4
[lightusage3] => 2
[lightcomment3] =>
)
[3] => Array
(
[lightwattage4] => 25
[lightvoltage4] => 12
[lightquantity4] => 2
[lightusage4] => 6
[lightcomment4] =>
)
)
我不确定你对元素或它们的顺序了解多少,所以这段代码基本上采用以数字结尾的任何元素集合,并将它们重新排列在具有相同结尾编号的组中。
答案 2 :(得分:0)
试试这个:
$outarr = array()
$subarr = array()
$i=0;
foreach($_POST as $key => $val)
{
//only include keys starting with light:
if (strpos("light", $key)==0)
{
//create a new subarray each time we find a key that starts with "lightwattage":
if ($i>0 && strpos("lightwattage", $key)==0)
{
$outarr[] = $subarr;
}
$subarr[$key] = $val;
$i++;
}
}
$outarr[] = $subarr;
//$outarr contains what you want here