Question

我想知道如何使用Matrix在旋转后获取矩形内的坐标的新位置。我想做的是：

定义矩形
在该矩形内定义坐标
旋转矩形
旋转后获取坐标的新位置

我无法弄清楚的部分是2＆amp; 4。有什么想法吗？

Answer 1

我为此创建了一个简单的Demo。它有一点额外的，所以你也可以看到如何在绘图中使用它。

main.xml中

<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:id="@+id/container"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent">
    <SeekBar
        android:id="@+id/seekBar1"
        android:layout_width="fill_parent"
        android:layout_height="wrap_content"
        android:layout_alignParentBottom="true"
        android:layout_centerHorizontal="true" />
</RelativeLayout>

活动：

package nl.entreco.android.testrotation;

import android.app.Activity;
import android.content.Context;
import android.graphics.Canvas;
import android.graphics.Color;
import android.graphics.Matrix;
import android.graphics.Paint;
import android.graphics.Point;
import android.graphics.Rect;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.RelativeLayout;
import android.widget.SeekBar;
import android.widget.SeekBar.OnSeekBarChangeListener;

public class RotationActivity extends Activity implements OnSeekBarChangeListener {


    private MyDrawing myDrawing;
    private SeekBar mSeekbar;

    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);

        Rect rect = new Rect(150,150,440,630);

        int x = (int) (rect.left + Math.random() * rect.width());
        int y = (int) (rect.top + Math.random() * rect.height());
        Point coordinate = new Point(x, y);


        // To draw the rect we create a CustomView
        myDrawing = new MyDrawing(this, rect, coordinate);

        RelativeLayout rl = (RelativeLayout)findViewById(R.id.container);
        rl.addView(myDrawing);


        mSeekbar = (SeekBar)findViewById(R.id.seekBar1);
        mSeekbar.setMax(360);
        mSeekbar.setOnSeekBarChangeListener(this);
    }

    private class MyDrawing extends View
    {
        private Rect myRect;
        private Point myPoint;
        private Paint rectPaint;
        private Paint pointPaint;

        private Matrix transform;

        public MyDrawing(Context context, Rect rect, Point point)
        {
            super(context);

            // Store the Rect and Point
            myRect = rect;
            myPoint = point;

            // Create Paint so we can see something :)
            rectPaint = new Paint();
            rectPaint.setColor(Color.GREEN);
            pointPaint = new Paint();
            pointPaint.setColor(Color.YELLOW);

            // Create a matrix to do rotation
            transform = new Matrix();

        }


        /**
        * Add the Rotation to our Transform matrix.
        * 
        * A new point, with the rotated coordinates will be returned
        * @param degrees
        * @return
        */
        public Point rotate(float degrees)
        {
            // This is to rotate about the Rectangles center
            transform.setRotate(degrees, myRect.exactCenterX(),     myRect.exactCenterY());

            // Create new float[] to hold the rotated coordinates
            float[] pts = new float[2];

            // Initialize the array with our Coordinate
            pts[0] = myPoint.x;
            pts[1] = myPoint.y;

            // Use the Matrix to map the points
            transform.mapPoints(pts);

            // NOTE: pts will be changed by transform.mapPoints call
            // after the call, pts will hold the new cooridnates

            // Now, create a new Point from our new coordinates
            Point newPoint = new Point((int)pts[0], (int)pts[1]);

            // Return the new point
            return newPoint;
        }

        @Override
        public void onDraw(Canvas canvas)
        {
            if(myRect != null && myPoint != null)
            {
                // This is an easy way to apply the same transformation (e.g. rotation)
                // To the complete canvas.
                canvas.setMatrix(transform);

                // With the Canvas being rotated, we can simply draw
                // All our elements (Rect and Point) 
                canvas.drawRect(myRect, rectPaint);
                canvas.drawCircle(myPoint.x, myPoint.y, 5, pointPaint);
            }
        }
    }

    @Override
    public void onProgressChanged(SeekBar seekBar, int progress,boolean fromUser) {

        Point newCoordinates = myDrawing.rotate(progress);


        // Now -> our float[] pts contains the new x,y coordinates
        Log.d("test", "Before Rotate myPoint("+newCoordinates.x+","+newCoordinates.y+")");
        myDrawing.invalidate();

    }

    @Override
    public void onStartTrackingTouch(SeekBar seekBar) {}

    @Override
    public void onStopTrackingTouch(SeekBar seekBar) {}
}

Answer 2

使用Matrix.mapPoints按矩阵转换2D点。

Answer 3

很长一段时间我知道，但这也是我仍然感到困惑的事情。整个API领域似乎更专注于为我们做事，而不是让我们了解实际发生的事情，毫无疑问，因为它在幕后做了非常聪明的事情。

设定点并将它们取回是完全分开的。

设置特定点有多种方法，Entreco的优秀答案显示了一种方式。

要获得一个点，您必须获得与该点相关联的矩阵的值，然后从中选择正确的部分。这个也非常好的答案（Android Matrix, what does getValues() return?）非常清楚地解释了矩阵发生了什么，你可以从中看出你想要的x，y值是2和5索引的元素。

以下是我用来获取它们的（稍微伪）代码。

float [] theArray = { <nine float zeroes> }
Matrix m = new Matrix();
boolean success = myPathMeasure.getMatrix(m, theArray, Matrix.MTRANS_X+Matrix.MTRANS_Y);
m.getValues(theArray);
x = theArray[2];
y = theArray[5];

我对此并不十分满意，但似乎没有更正式的方法来做到这一点。

使用Matrix旋转后获取坐标的新位置

3 个答案: