Question

我正在编写一个存储过程，我必须从db创建一个xml列。

µ = CHAR(181)这是值分隔符，

¶ = CHAR(182)这是行分隔符

这是我写的声明。我知道它不是很好。

SELECT @xmlString= CAST('<root><Section> ID =' + REPLACE(REPLACE ('20211µ1¶20212µ2', CHAR(182), 
        '</Section><Section> ID ='),CHAR(181), ' Slno=') + '</Section></root>' AS XML)

这是我需要这样显示的模式。

<root>
        <sections id="20211" slno="1" ></sections>
        <sections id="20215" slno="2" ></sections>
</root>

Answer 1

declare @s varchar(50) = '20211µ1¶20212µ2'
declare @xmlString xml

;with C as
(
  select T.N.value('value[1]', 'int') as id,
         T.N.value('value[2]', 'int') as slno
  from (select cast('<item><value>'+replace(replace(@s, 'µ','</value><value>'), '¶','</value></item><item><value>')+'</value></item>' as xml)) as X(XMLCol)
    cross apply X.XMLCol.nodes('item') as T(N)
)
select @xmlString = 
  (
   select C.id as [@id] ,
          C.slno as [@slno]
   from C
   for xml path('sections'), root('root'), type
  )

select @xmlString

结果：

<root>
  <sections id="20211" slno="1" />
  <sections id="20212" slno="2" />
</root>

如何从sql为以下模式生成xml

1 个答案: