Question

我希望使用PCRE C库递归匹配一个组。

e.g。

pattern = "(\d,)"
subject = "5,6,3,2,"
OVECCOUNT = 30

pcrePtr = pcre_compile(pattern, 0, &error, &erroffset, NULL);
rc = pcre_exec(pcrePtr, NULL, subject, (int)strlen(subject), 
0, 0, ovector, OVECCOUNT);

rc是-1 ..

如何匹配所有组以使匹配为“5”，“6”，“3”，“2”，

对于类比，PHP的preg_match_all解析整个字符串，直到主题结束......

Answer 1

试试这个：

pcre *myregexp;
const char *error;
int erroroffset;
int offsetcount;
int offsets[(0+1)*3]; // (max_capturing_groups+1)*3
myregexp = pcre_compile("\\d,", 0, &error, &erroroffset, NULL);
if (myregexp != NULL) {
    offsetcount = pcre_exec(myregexp, NULL, subject, strlen(subject), 0, 0, offsets, (0+1)*3);
    while (offsetcount > 0) {
        // match offset = offsets[0];
        // match length = offsets[1] - offsets[0];
        if (pcre_get_substring(subject, &offsets, offsetcount, 0, &result) >= 0) {
            // Do something with match we just stored into result
        }
        offsetcount = pcre_exec(myregexp, NULL, subject, strlen(subject), 0, offsets[1], offsets, (0+1)*3);
    } 
} else {
    // Syntax error in the regular expression at erroroffset
}

我认为这些评论是不言自明的？

Answer 2

我使用strtok的任何方式，因为“，”在每组之后重复...

欢迎使用pcre的解决方案......

pcre匹配C中的所有组

2 个答案: