我有一系列MySQL表,其中第一列是Unix时间格式的日期,第二列是每个表格具有不同格式的一些数据。
我使用与此类似的查询按月对数据进行分组:
SELECT YEAR(FROM_UNIXTIME(date)) AS year, MONTH(FROM_UNIXTIME(date)) AS month, SUM(views) AS views,
FROM stats
GROUP BY year, month
我需要什么样的查询才能在按行分组的一行中输出所有这些“第二”列? 即每个返回的行包含“年,月,视图,列2,列3”......
我尝试过使用UNION,但是,由于“第二”列都不同,它会为每个表返回一行。比如:
year1, month1, views, 0, 0...
year1, month1, 0, column2, 0...
year1, month1, 0, 0, column3...
year2, month2, views, 0, 0...
year2, month2, 0, column2, 0...
year2, month2, 0, 0, column3...
答案 0 :(得分:1)
您必须执行以下操作:
SELECT MAX(views) as views,
MAX(column2) as column2,
MAX(column3) as column3
FROM (
SELECT YEAR(FROM_UNIXTIME(date)) AS year,
MONTH(FROM_UNIXTIME(date)) AS month,
SUM(views) AS views,
0 AS column2,
0 AS column3
FROM stats
GROUP BY year, month
UNION
SELECT YEAR(FROM_UNIXTIME(date)) AS year,
MONTH(FROM_UNIXTIME(date)) AS month,
0 AS views,
sum(column2) AS column2,
0 AS column3
FROM stats
GROUP BY year, month
UNION
SELECT YEAR(FROM_UNIXTIME(date)) AS year,
MONTH(FROM_UNIXTIME(date)) AS month,
0 AS views,
0 AS column2,
sum(column3) AS column3
FROM stats
GROUP BY year, month
)
GROUP BY year, month;
由于每个选择包含相同的列,因此您将能够聚合整个事物并选择每行的最大值。显然,如果您的数据是非数字或小于0,则必须替换不同的聚合函数。