我想使用HTTPClient运行线程安全的异步HTTP请求。我注意到它不尊重我的CONNECTION_TIMEOUT
参数。
代码是ColdFusion / Java hybrid。
client = loader.create("org.apache.http.impl.nio.client.DefaultHttpAsyncClient").init();
CoreConnectionPNames = loader.create("org.apache.http.params.CoreConnectionPNames");
client.getParams()
.setIntParameter(JavaCast("string", CoreConnectionPNames.SO_TIMEOUT), 10)
.setIntParameter(JavaCast("string", CoreConnectionPNames.CONNECTION_TIMEOUT), 10);
client.start();
request = loader.create("org.apache.http.client.methods.HttpGet").init("http://www.google.com");
future = client.execute(request, javacast("null", ""));
try {
response = future.get();
}
catch(e any) {}
client.getConnectionManager().shutdown();
无论我为CONNECTION_TIMEOUT提供什么,请求总是返回200 OK。检查下面的输出。
输出
200 OK http://www.google.com/
200 OK http://www.google.com/
[snip]
5 requests using Async Client in: 2308 ms
答案 0 :(得分:3)
apache的HttpClient文档有些不稳定。在您的设置中尝试这个(它适用于版本4):
HttpConnectionParams.setConnectionTimeout(params, 10000);
HttpConnectionParams.setSoTimeout(params, 10000);
... set more parameters here if you want to ...
SchemeRegistry schemeRegistry = new SchemeRegistry();
.. do whatever you ant with the scheme registry here ...
ThreadSafeClientConnManager connectionManager = new ThreadSafeClientConnManager(params, schemeRegistry);
client = new DefaultHttpClient(connectionManager, params);
答案 1 :(得分:2)
您必须使用框架的类方法定义HttpParams对象。
HttpParams params = new BasicHttpParams();
HttpProtocolParams.setVersion(params, HttpVersion.HTTP_1_1);
HttpProtocolParams.setContentCharset(params, HTTP.UTF_8);
HttpConnectionParams.setConnectionTimeout(params, 2000);
SchemeRegistry registry = new SchemeRegistry();
registry.register(new Scheme("http", PlainSocketFactory.getSocketFactory(), 80));
registry.register(new Scheme("https", SSLSocketFactory.getSocketFactory(), 443));
ClientConnectionManager ccm = new ThreadSafeClientConnManager(params, registry);
HttpClient client = DefaultHttpClient(ccm, params);