我有这么简单的模型:
public abstract class Entity
{
public virtual Guid Id { get; protected set; }
}
public class Post : Entity
{
public String Title { get ; set; }
public String Content { get; set; }
public DateTime Timestamp { get; set; }
public Byte[] Thumbnail { get; set; }
}
public class Blog : Entity
{
public String Title { get; set; }
public ISet<Post> Posts { get; set; }
}
然后我有这样的映射:
BLOG
<?xml version="1.0" encoding="utf-8" ?>
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" auto-import="true assembly="Application.Domain" namespace="Application.Domain.Entities">
<class name="Blog">
<!-- id generator -->
<id name="Id">
<generator class="guid.comb" />
</id>
<!-- properties/columns -->
<property name="Title" not-null="true" />
<!-- components/columns -->
<!-- associations -->
<set name="Posts" cascade="all">
<!-- key column? -->
</set>
</class>
</hibernate-mapping>
POST
<?xml version="1.0" encoding="utf-8" ?>
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" auto-import="true" assembly="Application.Domain" namespace="Application.Domain.Entities">
<class name="Blog">
<!-- id generator -->
<id name="Id">
<generator class="guid.comb" />
</id>
<!-- properties/columns -->
<property name="Title" not-null="true" />
<property name="Content" not-null="true" />
<property name="Timestamp" not-null="true"/>
<property name="Thmbnail" />
<!-- components/columns -->
<!-- associations -->
</class>
</hibernate-mapping>
如何映射一对多关联(单向)?
谢谢!
答案 0 :(得分:1)
我认为这与描述here的问题相同。
而且,我认为你在Post-class名称的映射中有一个错误,不应该是Blog。此外,在您的示例中,Post与Blog没有任何关系。
答案 1 :(得分:1)
在博客映射文件中,您需要在引用表中引用one-to-many
实体的外键列之间定义Blog
关系,并说明它是BlogId
,您需要告诉它这个一对多关系与哪个类相关,在你的情况下,这将是Post
类,你需要用它的完全限定的命名空间来定义它,它包含这个类和一个逗号,然后汇编名称为以下内容:
<set name="Posts" table="Post">
<key column="BlogId"/>
<one-to-many class="Application.Domain.Entities.Post, Application.Domain"/>
</set>