Question

我想生成一个复杂的自连接查询抛出DQL。

这是我的表格结构的简单版本。

CREATE TABLE `item_view` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `id_item` int(11) NOT NULL,
  `id_user` int(11) DEFAULT NULL,
  PRIMARY KEY (`id`),
)

，实体将

    /**
     * @Column(name="id", type="integer", nullable=false)
     * @Id
     * @GeneratedValue(strategy="IDENTITY")
     */
    private $id;


     /**
     * @ManyToOne(targetEntity="User")
     * @JoinColumns({
     *   @JoinColumn(name="id_user", referencedColumnName="id_user")
     * })
     */
    private $user;

    /**
   * @ManyToOne(targetEntity="Item")
     * @JoinColumns({
     *   @JoinColumn(name="id_item", referencedColumnName="id_item")
     * })
     */
    private $item;

我很想生成像这样的查询:(

select 
    `c2`.*, count(`c1`.`id_user`) as `vc`
from
    `item_view` `c1`
        inner join
    `item_view` `c2` ON `c1`.`id_user` = `c2`.`id_user`
where
    `c1`.`id_item` in (6) and `c2`.`id_item` not in (6)
group by `c2`.`id_item`
order by `vc` desc

通过此本机查询，我可以选择常用的用户信息。

任何想法我们怎么做才能抛出DQL？

更新

我只是找到了解决桥梁关系的工作

SELECT v,COUNT(v.user) AS USR_CNT FROM ItemView v JOIN v.user u JOIN u.views v2 
WHERE v2.item IN (:items) and v NOT IN (:items)
GROUP BY v.item
ORDER BY USR_CNT DESC

将生成此SQL

SELECT 
    `i0_`.`id` AS `id0`,
    COUNT(`i0_`.`id_user`) AS `sclr2`,
    `i0_`.`id_user` AS `id_user3`,
    `i0_`.`id_item` AS `id_item4`
FROM
    `item_view` `i0_`
        INNER JOIN
    `user` `u1_` ON `i0_`.`id_user` = `u1_`.`id_user`
        INNER JOIN
    `item_view` `i2_` ON `u1_`.`id_user` = `i2_`.`id_user`
WHERE
    `i2_`.`id_item` IN (6) AND `i0_`.`id` NOT IN (6)
GROUP BY `i0_`.`id_item`
ORDER BY `sclr2` DESC

那么我们怎样才能消除用户表的额外连接？！

教义2自我加入

0 个答案: