Question

#Ask the user what option he wants        
mode = input("Would you like to count Vowel's or Consonant's ? (Vowel or Consonant): ")
mode = mode.strip()
mode = mode.lower()

# Tell the user the input he entered wasn't valid        
while mode != 'consonant' and mode != 'vowel':
        mode = input("That's not correct. Would you like to count Vowel's or Consonant's ? (Vowel or Consonant): ")
#get the word from the user
word = input("Please enter your Word: ")
vowel_count = 0
consonant_count = 0
for letter in word:
    if letter in 'aeiouAEIOU':
        vowel_count += 1

for letter in word:
    if letter in 'bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ':
        consonant_count += 1

if mode == "consonant":
        print(word,"contains", consonant_count, "consonant's")

if mode == "vowel":
        print(word,"contains", vowel_count, "vowel's")

程序启动并询问用户是否要计算元音或辅音，将其存储为“模式”。如果用户提供“辅音”或“元音”以外的输入，程序会将此解释为错误并重新请求输入。
程序要求一个字。
根据模式，计算辅音或元音的数量并报告给用户。
程序询问是否有其他单词可用。如果是，则重复步骤2到4，否则继续执行步骤5.
根据模式，向用户报告每个单词的平均元音或每个单词的平均辅音。

我坚持第4步，我不知道如何向对方要求另一个字并重复相同的过程

Answer 1

while c:
    do_stuff()
    c = raw_input('Do you want to contine y/n')
    if c.lower().startswith('y'):
        c = True
    else:
        c = False

需要询问用户是否要再试一次（Python）

1 个答案: