Question

我试图转换的XML看起来像：

<?xml version="1.0" encoding="utf-8"?>
<ArrayOfTrafiklage>
  <Trafiklage>
    <Utgangsdatum xmlns="">2011-10-14T00:00:00+02:00</Utgangsdatum>
  </Trafiklage>
  <Trafiklage>
    <Utgangsdatum xmlns="">2011-10-15T00:00:00+02:00</Utgangsdatum>
  </Trafiklage>
  <Trafiklage>
    <Utgangsdatum xmlns="">2011-10-16T00:00:00+02:00</Utgangsdatum>
  </Trafiklage>
</ArrayOfTrafiklage>

我要转换的代码如下所示：

XStream xstream = new XStream(new DomDriver());

xstream.alias("ArrayOfTrafiklage", Trafiklagen.class);
xstream.alias("Trafiklage", StationInfoModel.class);

Trafiklagen trafiklagen = (Trafiklagen) xstream
        .fromXML(result);

StationInfoModel.java看起来像：

public class StationInfoModel 
{
    private Date Utgangsdatum;
}

我在运行fromXML命令时遇到此异常：

com.thoughtworks.xstream.converters.ConversionException: Utgangsdatum : Utgangsdatum
---- Debugging information ----
message             : Utgangsdatum
cause-exception     : com.thoughtworks.xstream.mapper.CannotResolveClassException
cause-message       : Utgangsdatum
class               : java.util.ArrayList
required-type       : java.util.ArrayList
converter-type      : com.thoughtworks.xstream.converters.collections.CollectionConverter
path                : /ArrayOfTrafiklage/Trafiklage/Utgangsdatum
class[1]            : org.rickardp.trainstatus.Models.Trafiklagen
converter-type[1]   : com.thoughtworks.xstream.converters.reflection.ReflectionConverter
version             : 0.0
-------------------------------

有人知道我做错了吗？

Answer 1

看看这个blog article

Answer 2

使用此

private static SimpleDateFormat frmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.S z");

frmt.format(date)

xml日期和时间字符串上的XStream转换异常

2 个答案: