Question

我需要解析Android中的2D数组并将其作为意图传递给另一个活动。我该怎么做？

我从服务器获取以下2D数组作为响应。

[
{
    "sno": "131",
    "email": "ruma.riwaz@gmail.com",
    "place": "43",
    "description": "",
    "image": "",
    "time": "1316156532"
},
{
    "sno": "130",
    "email": "ruma.riwaz@gmail.com",
    "place": "38",
    "description": "",
    "image": "",
    "time": "1316153291"
},
{
    "sno": "365",
    "email": "ruma.riwaz@gmail.com",
    "place": "86",
    "description": "",
    "image": "",
    "time": "1318427821"
},
{
    "sno": "129",
    "email": "ruma.riwaz@gmail.com",
    "place": "39",
    "description": "",
    "image": "",
    "time": "1316152314"
},
{
    "sno": "371",
    "email": "ruma.riwaz@gmail.com",
    "place": "90",
    "description": "",
    "image": "",
    "time": "1318502879"
},
{
    "sno": "370",
    "email": "ruma.riwaz@gmail.com",
    "place": "89",
    "description": "",
    "image": "",
    "time": "1318495237"
},
{
    "sno": "366",
    "email": "ruma.riwaz@gmail.com",
    "place": "86",
    "description": "",
    "image": "",
    "time": "1318427852"
},
{
    "sno": "126",
    "email": "ruma.riwaz@gmail.com",
    "place": "43",
    "description": "",
    "image": "",
    "time": "1316149489"
},
{
    "sno": "125",
    "email": "ruma.riwaz@gmail.com",
    "place": "43",
    "description": "",
    "image": "",
    "time": "1316148422"
},
{
    "sno": "168",
    "email": "ruma.riwaz@gmail.com",
    "place": "39",
    "description": "",
    "image": "",
    "time": "1316265504"
},
{
    "sno": "368",
    "email": "ruma.riwaz@gmail.com",
    "place": "87",
    "description": "",
    "image": "",
    "time": "1318480496"
},
{
    "sno": "174",
    "email": "ruma.riwaz@gmail.com",
    "place": "39",
    "description": "",
    "image": "",
    "time": "1316667799"
},
{
    "sno": "176",
    "email": "ruma.riwaz@gmail.com",
    "place": "39",
    "description": "",
    "image": "",
    "time": "1316670052"
},
{
    "sno": "252",
    "email": "ruma.riwaz@gmail.com",
    "place": "54",
    "description": "",
    "image": "",
    "time": "1317471220"
},
{
    "sno": "300",
    "email": "ruma.riwaz@gmail.com",
    "place": "39",
    "description": "",
    "image": "",
    "time": "1317964945"
},
{
    "sno": "299",
    "email": "ruma.riwaz@gmail.com",
    "place": "39",
    "description": "",
    "image": "",
    "time": "1317964703"
},

如何解决此问题？

Answer 1

String json = "Set your JSON here";
JSONArray array = new JSONArray(json);
for(int i = 0; i < array.length(); i++){
    JSONObject object = array.getJSONObject(i);
    Strin sno = object.getString("sno");
    //Continue the parsing this way.
}

Answer 2

仅供参考， myObject 是我刚刚参考的类，并为此myObject类中的所有上述属性定义了getter和setter方法。现在，当您完成它时，请实现以下代码以准备JSON包含的所有项目的arraylist。

      ArrayList<myObject> listObject = new ArrayList<myObject>();
      myObject obj = null;

      try {
        JSONArray jArray = new JSONArray(str);
        for(int i = 0; i < jArray.length() ; i++)
        {
            JSONObject jObject = jArray.getJSONObject(i);
            obj = new myObject();
            obj.setSno(jObject.getString("sno"));
            obj.setEmail(jObject.getString("email"));
            obj.setPlace(jObject.getString("place"));
            obj.setDescription(jObject.getString("description"));
            obj.setImage(jObject.getString("image"));
            obj.setTime(jObject.getString("time"));

         /* Add the list item object to the ArrayList. At the end you will be
            having an arraylist of all items that you have parsed. */

            listObject.add(obj);
        }
    }
    catch (JSONException e2) {
        // TODO Auto-generated catch block
        e2.printStackTrace();
    }

Answer 3

尝试使用gson库。它有简单的toJson（）和fromJson（）方法，使得它很容易使用JSON和Java对象。

可以找到使用指南here

Answer 4

我写了小数据库：

https://github.com/ko5tik/jsonserializer

这项运动是什么

只需通过适当的课程（取自单元测试）将GSON读者传递给它：

 /**
  * unmarshalling of JSON array shall produce list
  */
@Test
public void testUnmarshallingOfJsonArray() throws InvocationTargetException, IOException, NoSuchMethodException, IllegalAccessException, InstantiationException {
    // must be lenient
    source = new JsonReader(new StringReader("[{one:239},{two:555}]"));
    source.setLenient(true);
    final List<WithTwoProperties> list = JSONUnmarshaller.unmarshallArray(source, WithTwoProperties.class);

    assertEquals(2, list.size());
    assertEquals(239, list.get(0).getOne());
    assertEquals(555, list.get(1).getTwo());
}

（Unmarshall Array需要数组元素的类，所以在这种情况下它将是有点像（new String []）。class）

Answer 5

你可以试试这种方式

        String str = "YOUR JSON STRING";
        try {
            JSONArray tempArr = new JSONArray(str);
            for(int i = 0; i < tempArr.length() ; i++)
            {
                JSONObject obj = tempArr.optJSONObject(i);
                Log.i("TAG",obj.getString("sno"));
                Log.i("TAG",obj.getString("email"));
                Log.i("TAG",obj.getString("place"));
                Log.i("TAG",obj.getString("description"));
                Log.i("TAG",obj.getString("image"));
                Log.i("TAG",obj.getString("time"));             
            }
        } catch (JSONException e2) {
            // TODO Auto-generated catch block
            e2.printStackTrace();
        }

在Android中解析2D JSON数组，然后将它们置于意图中并在另一个活动中获取它们的值

5 个答案: