我正在创建一个Windows服务，并且正在尝试访问我添加到资源文件中的一些文件，但我因为不知道如何访问单个文件而陷入困境。仅仅为了一些背景信息，这是我到目前为止所做的：
这是一个在调试模式下作为控制台应用程序运行的C＃Windows服务应用程序，它可以帮助我进入代码。
我在根目录中添加了一个名为“Resources.resx”的资源文件。
在我的资源文件中，我使用可视化设计器/编辑器添加了一些jpg图像和html文件。
将图像和html文件添加到资源文件后，我的项目中的新文件夹显示为“Resources”，其中包含我添加的所有文件。
在这个新文件夹中，我转到了每个文件的属性，并将Build Action更改为Embedded Resource。 （我不知道这是否有必要。我搜索的一些博客说试试。）
项目的名称空间名为“MicroSecurity.EmailService”。
为了获取资源文件的名称，我使用了
的GetType（）。Assembly.GetManifestResourceNames（）
我得到以下
GetType（）。Assembly.GetManifestResourceNames（）{string [2]} string [] [0]“MicroSecurity.EmailService.Services.EmailService.resources”字符串 [1]“MicroSecurity.EmailService.Resources.resources”字符串
由此我发现“MicroSecurity.EmailService.Resources.resources”是我想要使用的字符串（索引1）。
我使用此代码获取流对象。
var stream = Assembly.GetExecutingAssembly（）。GetManifestResourceStream（“MicroSecurity.EmailService.Resources.resources”）;
当我在调试期间向此变量添加监视时，我可以看到诸如图像元数据之类的内容等。
这是我被困的地方。我想访问名为“logo.jpg”的图像。这就是我正在做的事情，但它不起作用。
var stream = Assembly.GetExecutingAssembly().GetManifestResourceStream("MicroSecurity.EmailService.Resources.resources.logo.jpg");
如何从logo.jpg文件中获取流？
更新：
感谢Andrew，我能够弄清楚。下面是我为演示项目编写的一些代码，以便研究资源文件如何工作而不是直接嵌入文件。我希望这有助于其他人澄清差异。
using System;
using System.Drawing;
using System.IO;
using System.Reflection;
namespace UsingResourceFiles
{
public class Program
{
/// <summary>
/// Enum to indicate what type of file a resource is.
/// </summary>
public enum FileType
{
/// <summary>
/// The resource is an image.
/// </summary>
Image,
/// <summary>
/// The resource is something other than an image or text file.
/// </summary>
Other,
/// <summary>
/// The resource is a text file.
/// </summary>
Text,
}
public static void Main(string[] args)
{
// There are two ways to reference resource files:
// 1. Use embedded objects.
// 2. Use a resource file.
// Get the embedded resource files in the Images and Text folders.
UseEmbeddedObjects();
// Get the embedded resource files in the Images and Text folders. This allows for dynamic typing
// so the resource file can be returned either as a stream or an object in its native format.
UseEmbeddedObjectsViaGetResource();
// Use the zombie.gif and TextFile.txt in the Resources.resx file.
UseResourceFile();
}
public static void UseEmbeddedObjects()
{
// =============================================================================================================================
//
// -=[ Embedded Objects ]=-
//
// This way is the easiest to accomplish. You simply add a file to your project in the directory of your choice and then
// right-click the file and change the "Build Action" to "Embedded Resource". When you reference the file, it will be as an
// unmanaged stream. In order to access the stream, you'll need to use the GetManifestResourceStream() method. This method needs
// the name of the file in order to open it. The name is in the following format:
//
// Namespace + Folder Path + File Name
//
// For example, in this project the namespace is "UsingResourceFiles", the folder path is "Images" and the file name is
// "zombie.gif". The string is "UsingResourceFiles.Images.zombie.gif".
//
// For images, once the image is in a stream, you'll have to convert it into a Bitmap object in order to use it as an Image
// object. For text, you'll need to use a StreamReader to get the text file's text.
// =============================================================================================================================
var imageStream = Assembly.GetExecutingAssembly().GetManifestResourceStream("UsingResourceFiles.Images.zombie.gif");
var image = new Bitmap(imageStream);
var textStream = Assembly.GetExecutingAssembly().GetManifestResourceStream("UsingResourceFiles.Text.TextFile.txt");
var text = new StreamReader(textStream).ReadToEnd();
}
public static void UseEmbeddedObjectsViaGetResource()
{
// =============================================================================================================================
//
// -=[ Embedded Objects Using GetResource() ]=-
//
// Using the overloaded GetResource() method, you can easily obtain an embedded resource file by specifying the dot file path
// and type. If you need the stream version of the file, pass in false to the useNativeFormat argument. If you use the
// GetResource() method outside of this file and are getting a null value back, make sure you set the resource's "Build Action"
// to "Embedded Resource".
// =============================================================================================================================
// Use the GetResource() methods to obtain the Images\zombie.gif file and the text from the Text\TextFile.txt file.
Bitmap image = GetResource("Images.zombie.gif", FileType.Image);
Stream imageStream = GetResource("Images.zombie.gif", FileType.Image, false);
string text = GetResource("Text.TextFile.txt", FileType.Text);
Stream textStream = GetResource("Text.TextFile.txt", FileType.Text, false);
}
public static void UseResourceFile()
{
// =============================================================================================================================
//
// -=[ Resource File ]=-
//
// This way takes more upfront work, but referencing the files is easier in the code-behind. One drawback to this approach is
// that there is no way to organize your files in a folder structure; everything is stuffed into a single resource blob.
// Another drawback is that once you create the resource file and add any files to it, a folder with the same name as your
// resource file is created, creating clutter in your project. A final drawback is that the properties of the Resources object
// may not follow proper C# naming conventions (e.g. "Resources.funny_man" instead of "Resources.FunnyMan"). A plus for using
// resource files is that they allow for localization. However, if you're only going to use the resource file for storing files,
// using the files as embedded objects is a better approach in my opinion.
// =============================================================================================================================
// The Resources object references the resource file called "Resources.resx".
// Images come back as Bitmap objects and text files come back as string objects.
var image = Resources.zombie;
var text = Resources.TextFile;
}
/// <summary>
/// This method allows you to specify the dot file path and type of the resource file and return it in its native format.
/// </summary>
/// <param name="dotFilePath">The file path with dots instead of backslashes. e.g. Images.zombie.gif instead of Images\zombie.gif</param>
/// <param name="fileType">The type of file the resource is.</param>
/// <returns>Returns the resource in its native format.</returns>
public static dynamic GetResource(string dotFilePath, FileType fileType)
{
try
{
var assembly = Assembly.GetExecutingAssembly();
var assemblyName = assembly.GetName().Name;
var stream = assembly.GetManifestResourceStream(assemblyName + "." + dotFilePath);
switch (fileType)
{
case FileType.Image:
return new Bitmap(stream);
case FileType.Text:
return new StreamReader(stream).ReadToEnd();
default:
return stream;
}
}
catch (Exception e)
{
Console.WriteLine(e);
return null;
}
}
/// <summary>
/// This method allows you to specify the dot file path and type of the resource file and return it in its native format.
/// </summary>
/// <param name="dotFilePath">The file path with dots instead of backslashes. e.g. Images.zombie.gif instead of Images\zombie.gif</param>
/// <param name="fileType">The type of file the resource is.</param>
/// <param name="useNativeFormat">Indicates that the resource is to be returned as resource's native format or as a stream.</param>
/// <returns>When "useNativeFormat" is true, returns the resource in its native format. Otherwise it returns the resource as a stream.</returns>
public static dynamic GetResource(string dotFilePath, FileType fileType, bool useNativeFormat)
{
try
{
if (useNativeFormat)
{
return GetResource(dotFilePath, fileType);
}
var assembly = Assembly.GetExecutingAssembly();
var assemblyName = assembly.GetName().Name;
return assembly.GetManifestResourceStream(assemblyName + "." + dotFilePath);
}
catch (Exception e)
{
Console.WriteLine(e);
return null;
}
}
}
}
答案 0 :(得分：11)
如果将Resources文件夹中的文件设置为Embedded Resource，那么您应该已经在GetManifestResourceNames（）调用中看到它。你可以试试
var stream = Assembly.GetExecutingAssembly().GetManifestResourceStream("MicroSecurity.EmailService.Resources.logo.jpg");
如果名称位于Resources文件夹中，则名称应为“MicroSecurity.EmailService.Resources.logo.jpg”。但是，将文件本身标记为嵌入式资源会破坏资源文件的目的（图像本身将嵌入两次）。
您可以完全删除资源文件，并将每个文件设置为嵌入式资源。此时，每个文件应该有单独的清单资源。在C＃项目中，每个文件名都将以项目命名空间+子文件夹为前缀。例如。如果在Resources / Embedded文件夹中添加“logo.jpg”文件，则资源名称将为“MicroSecurity.EmailService.Resources.Embedded.logo.jpg”。
或者，从Resources文件中获取位图并将其转换为流。您可以在How do I convert a Bitmap to byte[]?
中找到将Bitmap转换为MemoryStream的示例
答案 1 :(得分：1)
你能用：
System.Drawing.Bitmap myLogo = MicroSecurity.Properties.Resources.logo;
答案 2 :(得分：0)
public static readonly Func<string, object> GetDataByType = (path) => {
var fromStream = Assembly.GetExecutingAssembly().GetManifestResourceStream(path);
var formatter = new BinaryFormatter();
if (fromStream != null) {
var obj = formatter.Deserialize(fromStream);
fromStream.Close();
return obj;
}
return null;
};
var test GetDataByType("Resources.logo");
答案 3 :(得分：0)
circle :{
height : 30 ,
width :30,
borderRadius: 1000,
}
查看他如何在resx中嵌入图标文件 https://www.technical-recipes.com/2017/how-to-use-resource-files-in-your-csharp-project/