生成有效的网址Google Places API

时间:2011-10-13 14:47:44

标签: java google-maps google-api

我正在开发一个必须执行Google Places API请求的应用程序。

http://code.google.com/intl/es/apis/maps/documentation/places/

我在以下网站上获得了私钥:

https://code.google.com/apis/console

客户ID:XXXXXXXXXXX.apps.googleusercontent.com

客户机密:YYYYYYYYYYYYYYYYYYY(看起来像vNIXE0xscrmjlyV-12Nj_BvUPaw =)

我正在使用此代码生成网址:

public class UrlSigner {

  // Note: Generally, you should store your private key someplace safe
  // and read them into your code

  private static String keyString = "YYYYYYYYYYYYYYYYYY";

  // The URL shown in these examples must be already
  // URL-encoded. In practice, you will likely have code
  // which assembles your URL from user or web service input
  // and plugs those values into its parameters.
  private static String urlString = "http://maps.google.com/maps/api/place/search/json?location=40.717859,-73.957790&radius=1600&client=XXXXXXXXXXX.apps.googleusercontent.com&sensor=false";

  // This variable stores the binary key, which is computed from the string (Base64) key
  private static byte[] key;

  public static void main(String[] args) throws IOException,
    InvalidKeyException, NoSuchAlgorithmException, URISyntaxException {

    // Convert the string to a URL so we can parse it
    URL url = new URL(urlString);

    UrlSigner signer = new UrlSigner(keyString);
    String request = signer.signRequest(url.getPath(),url.getQuery());

    System.out.println("Signed URL :" + url.getProtocol() + "://" + url.getHost() + request);
  }

  public UrlSigner(String keyString) throws IOException {
    // Convert the key from 'web safe' base 64 to binary
    keyString = keyString.replace('-', '+');
    keyString = keyString.replace('_', '/');
    System.out.println("Key: " + keyString);
    this.key = Base64.decode(keyString);
  }

  public String signRequest(String path, String query) throws NoSuchAlgorithmException,
    InvalidKeyException, UnsupportedEncodingException, URISyntaxException {

    // Retrieve the proper URL components to sign
    String resource = path + '?' + query;

    // Get an HMAC-SHA1 signing key from the raw key bytes
    SecretKeySpec sha1Key = new SecretKeySpec(key, "HmacSHA1");

    // Get an HMAC-SHA1 Mac instance and initialize it with the HMAC-SHA1 key
    Mac mac = Mac.getInstance("HmacSHA1");
    mac.init(sha1Key);

    // compute the binary signature for the request
    byte[] sigBytes = mac.doFinal(resource.getBytes());

    // base 64 encode the binary signature
    String signature = Base64.encodeBytes(sigBytes);

    // convert the signature to 'web safe' base 64
    signature = signature.replace('+', '-');
    signature = signature.replace('/', '_');

    return resource + "&signature=" + signature;
  }
}

代码工作正常:它返回一个URL,但URL给出了这个错误:

  
      
  1. 这是一个错误。   在此服务器上找不到请求的URL / maps / api / place / search / json?。(...)。这就是我们所知道的。
  2.   

我尝试通过XXXXXXXXXXX更改ClientID(XXXXXXXXXXX.apps.googleusercontent.com),但它仍然无效。谁知道我做错了什么?

非常感谢!

1 个答案:

答案 0 :(得分:0)

问题是你在谷歌方面没有达到任何终点。即使没有地方 - api-service也能满足您的要求。

尝试使用以下urlString:

private static String urlString = "http://maps.googleapis.com/maps/api/place/search/json?location=..."

重要的区别是googleapis而不是google。在浏览器中输入您创建的URL然后您会看到,您获得了一些json(即使它是被拒绝的请求)。然后你知道你达到了api-endpoint。

修改:我认为Google最近已将域名更改为googleapis。您使用的西班牙语文档使用google,英语文档使用googleapis。我认为西班牙语文档不是最新的。也许你把这些信息发布到谷歌(可能在论坛上)