NSURLRequest：如何将httpMethod“GET”更改为“POST”

Question

GET方法，它运作正常。

url：http://myurl.com/test.html?query=id=123&name=kkk

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我没有POST方法的概念。请帮帮我。

如何将GET方法转换为POST方法？

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url：http://testurl.com/test.html

[urlRequest setHTTPMethod:@"POST"];

Answer 1

试试这个

NSString *post = [NSString stringWithFormat:@"username=%@&password=%@",username.text,password.text];
NSLog(@"%@",post);
NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];

NSString *postLength = [NSString stringWithFormat:@"%d",[postData length]];
NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease];
[request setURL:[NSURL URLWithString:[NSString stringWithFormat:@" server link here"]]];
[request setHTTPMethod:@"POST"];
NSString *json = @"{}";
NSMutableData *body = [[NSMutableData alloc] init];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Current-Type"];
[request setHTTPBody:postData];
//get response
NSHTTPURLResponse* urlResponse = nil;  
NSError *error = [[NSError alloc] init];  
NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&urlResponse error:&error];  
NSString *result = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding];
NSLog(@"Response Code: %d", [urlResponse statusCode]);

if ([urlResponse statusCode] >= 200 && [urlResponse statusCode] < 300) 
{
    NSLog(@"Response: %@", result);
}

Answer 2

// create mutable request
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];       
// set GET or POST method
[request setHTTPMethod:@"POST"];
// adding keys with values
NSString *post = @"query=id=123&name=kkk";
NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
NSString *postLength = [NSString stringWithFormat:@"%d",[postData length]];
[request addValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setHTTPBody:postData];