Question

我想从“MAU120”中获取字符串“MAU”和“120”

来自“MAUL345”的

和“MAUL”和“345”。

“MAUW”和“MAUW23”中的“23”

请在PHP中建议一系列代码。

Answer 1

$matches = array();

if ( preg_match('/^([A-Z]+)([0-9]+)$/i', 'MAUL345', $matches) ) {
    echo $matches[1]; // MAUL
    echo $matches[2]; // 345 
}

如果您需要MAU，则可以执行以下操作：

/^(MAU[A-Z]*)([0-9]+)$/i

最后删除i修饰符会使正则表达式区分大小写。

Answer 2

试试这个正则表达式：

/(\D*)(\d*)/

PHP代码：

$matches = array();

var_dump( preg_match('/(\D*)(\d*)/', 'MAUL345', $matches) );
var_dump( $matches );

Answer 3

从字面上看你的例子：

<?php
$tests = array('MAU120', 'MAUL345', 'MAUW23', 'bob2', '?@#!123', 'In the MAUX123 middle.');

header('Content-type: text/plain');
foreach($tests as $test)
{
    preg_match('/(MAU[A-Z]?)(\d+)/', $test, $matches);
    $str = isset($matches[1]) ? $matches[1] : '';
    $num = isset($matches[2]) ? $matches[2] : '';
    printf("\$str = %s\n\$num = %d\n\n", $str, $num);
}
?>

产地：

$test = MAU120
$str = MAU
$num = 120

$test = MAUL345
$str = MAUL
$num = 345

$test = MAUW23
$str = MAUW
$num = 23

$test = bob2
$str = 
$num = 0

$test = ?@#!123
$str = 
$num = 0

$test = In the MAUX123 middle.
$str = MAUX
$num = 123

我想在第一个数字出现之前从字符串中获取子字符串

3 个答案: