Question

我正在尝试从iPhone / iPad向php服务发送多行帖子，问题是出于某种原因，POST Content-Type似乎是application / x-www-form-urlenconded，（我用Wireshark发现了这个）

这实际上是Wireshark POST数据包捕获的片段：

    **Content-Type: application/x-www-form-urlencoded\r\n**
    Content-Length: 324\r\n
        [Content length: 324]
    Connection: keep-alive\r\n
    \r\n
    [Full request URI: http://my.server.com/mobile/tools/authentication]
Line-based text data: application/x-www-form-urlencoded
    --0xKhTmLbOuNdArY\r\n
    Content-Disposition: form-data; name="login"\r\n
    \r\n
    hello@hello.com\r\n
    --0xKhTmLbOuNdArY\r\n
    Content-Disposition: form-data; name="password"\r\n
    \r\n
    somepassword\r\n
    --0xKhTmLbOuNdArY\r\n
    \r\n
    --0xKhTmLbOuNdArY--\r\n

问题是在服务器中我试图从这个POST请求中读取登录名和密码变量，但是因为我认为php认为POST请求是x-www-form-urlencoded所以不可能，所以如果我设置{ {1}}要做：

authentication.php

我明白了：

<?php
echo("<pre>")
print_r($_POST)
echo("</pre>")
?>

这显然不太好，因为如果我使用这个简单的html表单发送请求：

<pre>Array\n
(\n
    [--0xKhTmLbOuNdArY\r\n
Content-Disposition:_form-data;_name] => "login"\r\n
\r\n
hello@hello.com\r\n
--0xKhTmLbOuNdArY\r\n
Content-Disposition: form-data; name="password"\r\n
\r\n
somepassword\r\n
--0xKhTmLbOuNdArY\r\n
\r\n
--0xKhTmLbOuNdArY--\r\n
\n
)\n
</pre>

我从表单中获得了预期的Wireshark跟踪：

<FORM action="http://my.server.com/mobile/tools/authentication.php" method="post">
   <P>
   <LABEL for="login">E-mail: </LABEL>
             <INPUT type="text" name="login"><BR>
   <LABEL for="password">pass: </LABEL>
             <INPUT type="text" name="password"><BR>
   <INPUT type="submit" value="Send"> <INPUT type="reset">
   </P>
</FORM>

此文字输出来自Content-Type: application/x-www-form-urlencoded\r\n Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8\r\n Accept-Encoding: gzip,deflate,sdch\r\n Accept-Language: en-US,en;q=0.8\r\n Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.3\r\n Cookie: PHPSESSID=tpp10pbrdkkf5dg9qprlamfuu2\r\n \r\n [Full request URI: http://mymed2.sophia.inria.fr/mobile/tools/authentication.php] Line-based text data: application/x-www-form-urlencoded login=hello%40hello.com&password=somepassword

中的print_r($_POST)

authentication.php

这是我在Objective-C和Cocoa

中制作POST请求的方式

<pre>Array\n
(\n
    [login] => hello@hello.com\n
    [password] => somepassword\n
)\n
</pre>

如你所见，我开始做：

- (NSMutableURLRequest *) POSTRequestWithURL:(NSURL *)url andDataDictionary:(NSDictionary *) dictionary
{
    // Create a POST request
    NSMutableURLRequest *myMedRequest = [NSMutableURLRequest requestWithURL:url];
    [myMedRequest setHTTPMethod:@"POST"];

    // Add HTTP header info
    // Note: POST boundaries are described here: http://www.vivtek.com/rfc1867.html
    // and here http://www.w3.org/TR/html4/interact/forms.html
    NSString *POSTBoundary = [NSString stringWithString:@"0xKhTmLbOuNdArY"];
    [myMedRequest addValue:[NSString stringWithFormat:@"multipart/form-data; boundary=%@\r\n", POSTBoundary] forHTTPHeaderField:@"Content-Type"];

    // Add HTTP Body
    NSMutableData *POSTBody = [NSMutableData data];
    [POSTBody appendData:[[NSString stringWithFormat:@"--%@\r\n",POSTBoundary] dataUsingEncoding:NSUTF8StringEncoding]];

    // Add Key/Values to the Body
    NSEnumerator *enumerator = [dictionary keyEnumerator];
    NSString *key;

    while ((key = [enumerator nextObject])) {
        [POSTBody appendData:[[NSString stringWithFormat:@"Content-Disposition: form-data; name=\"%@\"\r\n\r\n", key] dataUsingEncoding:NSUTF8StringEncoding]];
        [POSTBody appendData:[[NSString stringWithFormat:@"%@", [dictionary objectForKey:key]] dataUsingEncoding:NSUTF8StringEncoding]];
        [POSTBody appendData:[[NSString stringWithFormat:@"\r\n--%@\r\n", POSTBoundary] dataUsingEncoding:NSUTF8StringEncoding]];
    }

    // Add the closing -- to the POST Form
    [POSTBody appendData:[[NSString stringWithFormat:@"\r\n--%@--\r\n", POSTBoundary] dataUsingEncoding:NSUTF8StringEncoding]]; 

    // Add the body to the myMedRequest & return
    [myMedRequest setHTTPBody:POSTBody];
    return myMedRequest;
}

但在之前的Wireshark跟踪日志中，POST数据包被视为Content-Type：application / x-www-form-urlencoded，也许我正在做其他错误的事情？

谢谢：）

编辑：顺便说一下，ASIHTTPRequest开发已经被首席开发人员放弃了here

，我希望避免像ASIHTTPRequest这样的外部框架

Answer 1

好的，因为我找不到没有外部库的解决方案，我修改了我的代码并open sourced，以防万一有人想要使用它。

我发布的代码的问题是

[myMedRequest addValue:[NSString stringWithFormat:@"multipart/form-data; boundary=%@\r\n", POSTBoundary] forHTTPHeaderField:@"Content-Type"];

删除修复所有内容。

希望这有助于其他人：）

从iOS发送多部分POST并在PHP $ _POST中读取参数？

1 个答案: