我正在尝试构建复杂的mysql查询,但它返回错误的结果......
SELECT
b.name AS batch_name,
b.id AS batch_id,
COUNT(DISTINCT s.id)
AS total_students,
COALESCE( SUM(s.open_bal), 0 )
AS open_balance,
SUM( COALESCE(i.reg_fee, 0)
+ COALESCE(i.tut_fee, 0)
+ COALESCE(i.other_fee, 0)
) AS gross_fee,
SUM( COALESCE(i.discount, 0) )
AS discount,
COALESCE( SUM(s.open_bal), 0 )
+ SUM( COALESCE(i.reg_fee, 0)
+ COALESCE(i.tut_fee, 0)
+ COALESCE(i.other_fee, 0)
)
- SUM( COALESCE(i.discount, 0) )
AS net_payable,
SUM( COALESCE(r.reg_fee, 0)
+ COALESCE(r.tut_fee, 0)
+ COALESCE(r.other_fee, 0)
) AS net_recieved,
( COALESCE( SUM(s.open_bal), 0 )
+ SUM( COALESCE(i.reg_fee, 0)
+ COALESCE(i.tut_fee, 0)
+ COALESCE(i.other_fee, 0)
)
- SUM( COALESCE(i.discount, 0) )
)
- ( SUM( COALESCE(r.reg_fee, 0)
+ COALESCE(r.tut_fee, 0)
+ COALESCE(r.other_fee, 0)
)
)
AS balance_due
FROM batches b
LEFT JOIN students s ON s.batch = b.id
LEFT JOIN invoices i ON i.student_id = s.id
LEFT JOIN recipts r ON r.student_id = s.id
WHERE s.inactive = 0
GROUP BY b.name, b.id;
返回以下结果......
| batch_name | total_students | open_bal | gross_fee | discount | net_payable | net_recieved | due_balance |
+------------+-----------------+----------+-----------+----------+-------------+--------------+-------------+
| MS | 6 | 10000 | 0 | 0 | 10000 | 101000 | -91000 |
+------------+-----------------+----------+-----------+----------+-------------+--------------+-------------+
批量表
| id | name |
+-----+------+
| 9 | Ms |
+-----+------+
学生表
| id | open_bal | batch | inactive |
+-----+----------+-------+----------+
| 44 | -16000 | 9 | 0 |
+-----+----------+-------+----------+
| 182 | 9000 | 9 | 0 |
+-----+----------+-------+----------+
| 184 | -36000 | 9 | 0 |
+-----+----------+-------+----------+
| 185 | 19000 | 9 | 0 |
+-----+----------+-------+----------+
| 186 | 9000 | 9 | 0 |
+-----+----------+-------+----------+
| 187 | 4000 | 9 | 0 |
+-----+----------+-------+----------+
发票表
| id | student_id | reg_fee | tut_fee | other_fee | net_payable | discount |
+------+------------+---------+---------+-----------+-------------+----------+
| | | | | | | |
+------+------------+---------+---------+-----------+-------------+----------+
上述学生ID没有发票。
收件表
| id | student_id | reg_fee | tut_fee | other_fee | status |
+------+------------+---------+---------+-----------+------------+
| 8 | 44 | 0 | 0 | 1500 | confirmed |
+------+------------+---------+---------+-----------+------------+
| 277 | 44 | 0 | 50000 | 0 | confirmed |
+------+------------+---------+---------+-----------+------------+
| 26 | 182 | 0 | 0 | 1500 | confirmed |
+------+------------+---------+---------+-----------+------------+
| 424 | 182 | 0 | 15000 | 0 | confirmed |
+------+------------+---------+---------+-----------+------------+
| 468 | 182 | 0 | 15000 | 0 | confirmed |
+------+------------+---------+---------+-----------+------------+
| 36 | 185 | 0 | 0 | 1500 | confirmed |
+------+------------+---------+---------+-----------+------------+
| 697 | 185 | 0 | 15000 | 0 | confirmed |
+------+------------+---------+---------+-----------+------------+
| 66 | 187 | 0 | 0 | 1500 | confirmed |
+------+------------+---------+---------+-----------+------------+
使用上述sql查询和表格的预期结果......
| batch_name | total_students | open_bal | gross_fee | discount | net_payable | net_recieved | due_balance |
+------------+-----------------+----------+-----------+----------+-------------+--------------+-------------+
| MS | 6 | -11000 | 0 | 0 | 10000 | 101000 | -112000 |
+------------+-----------------+----------+-----------+----------+-------------+--------------+-------------+
答案 0 :(得分:1)
你仍然没有提供完整的信息 - 没有批处理表,甚至没有现有的recipts表..无论如何,我认为我们不关心批处理表中的什么,让我们说它只是名称和ID。您的收据表为同一个学生提供了多行。由于所有JOIN,这应该导致为其他表返回多行。因此,SUM()多次为必须求和的值,即open_balance。这可能是问题出在何处的线索,我说你必须将你需要的信息从收据表移动到子查询中,但我不确定你是否向我们展示了你的整个数据库。尝试从查询中删除收据表并再次检查结果。如果就是这样,你应该看看从那里开始做什么或至少给我们更多的信息。
修改强> 查询应为:
SELECT
b.name AS batch_name,
b.id AS batch_id,
COUNT(DISTINCT s.id)
AS total_students,
COALESCE( SUM(s.open_bal), 0 )
AS open_balance,
SUM( COALESCE(i.reg_fee, 0)
+ COALESCE(i.tut_fee, 0)
+ COALESCE(i.other_fee, 0)
) AS gross_fee,
SUM( COALESCE(i.discount, 0) )
AS discount,
COALESCE( SUM(s.open_bal), 0 )
+ SUM( COALESCE(i.reg_fee, 0)
+ COALESCE(i.tut_fee, 0)
+ COALESCE(i.other_fee, 0)
)
- SUM( COALESCE(i.discount, 0) )
AS net_payable,
SUM((SELECT SUM(COALESCE(receipts.reg_fee, 0)
+ COALESCE(receipts.tut_fee, 0)
+ COALESCE(receipts.other_fee, 0)) FROM receipts WHERE receipts.student_id = s.id))
AS net_recieved,
( COALESCE( SUM(s.open_bal), 0 )
+ SUM( COALESCE(i.reg_fee, 0)
+ COALESCE(i.tut_fee, 0)
+ COALESCE(i.other_fee, 0)
)
- SUM( COALESCE(i.discount, 0) )
)
- SUM((SELECT SUM(COALESCE(receipts.reg_fee, 0)
+ COALESCE(receipts.tut_fee, 0)
+ COALESCE(receipts.other_fee, 0)) FROM receipts WHERE receipts.student_id = s.id))
AS balance_due
FROM batches b
LEFT JOIN students s ON s.batch = b.id
LEFT JOIN invoices i ON i.student_id = s.id
WHERE s.inactive = 0
GROUP BY b.name, b.id;
这将汇总收据表中的学生数据,即使它在多行上,只返回一行。将联接删除到收据表将从其他表中删除重复的行,因此现在计算应该是正确的。
还有一件事 - 你在WHERE子句中得到s.inactive = 0
,确保它与这个计算无关。
P.S。你怎么不知道子查询是什么,你最终写这样的东西?
答案 1 :(得分:0)
我已经得到了解决方案,我一起加入了大量的查询,而且一些结果是加倍的。感谢。