示例:
http://example.com/?a=text&q2=text2&q3=text3&q2=text4
删除“ q2 ”后,它将返回:
http://example.com/?q=text&q3=text3
在这种情况下,有多个“ q2 ”并且已全部删除。
答案 0 :(得分:54)
import sys
if sys.version_info.major == 3:
from urllib.parse import urlencode, urlparse, urlunparse, parse_qs
else:
from urllib import urlencode
from urlparse import urlparse, urlunparse, parse_qs
url = 'http://example.com/?a=text&q2=text2&q3=text3&q2=text4'
u = urlparse(url)
query = parse_qs(u.query)
query.pop('q2', None)
u = u._replace(query=urlencode(query, True))
print(urlunparse(u))
答案 1 :(得分:17)
import urlparse
url = 'http://example.com/?a=text&q2=text2&q3=text3&q2=text4'
urlparse.urljoin(url, urlparse.urlparse(url).path)
答案 2 :(得分:10)
使用python的url操作库 furl :
import furl
f = furl.furl("http://example.com/?a=text&q2=text2&q3=text3&q2=text4")
f.remove(['q2'])
print(f.url)
答案 3 :(得分:2)
import cgi
import urlparse
url = "http://example.com/?a=text&q2=text2&q3=text3&q2=text4"
qs = cgi.parse_qs(urlparse.urlparse(url)[4])
del(qs['q2'])
print qs
...明确
>>> import cgi
>>> import urlparse
>>> url = "http://example.com/?a=text&q2=text2&q3=text3&q2=text4"
>>> qs = cgi.parse_qs(urlparse.urlparse(url)[4])
>>> del(qs['q2'])
>>> print qs
{'a': ['text'], 'q3': ['text3']}
>>>
答案 4 :(得分:2)
这不仅仅是在字符上分割字符串的问题吗?
>>> url = http://example.com/?a=text&q2=text2&q3=text3&q2=text4
>>> url = url.split('?')[0]
'http://example.com/'
答案 5 :(得分:1)
query_string = "https://example.com/api/api.php?user=chris&auth=true"
url = query_string[:query_string.find('?', 0)]
答案 6 :(得分:0)
或者简单地说,只需使用url_query_cleaner()
中的w3lib.url
from w3lib.url import url_query_cleaner
url = 'http://example.com/?a=text&q2=text2&q3=text3&q2=text4'
url_query_cleaner(url, ('q2'), remove=True)
输出:http://example.com/?a=text&q3=text3
答案 7 :(得分:-3)
import re
q ="http://example.com/?a=text&q2=text2&q3=text3&q2=text4"
todelete="q2"
#Delete every query string matching the pattern
r = re.sub(r''+todelete+'=[a-zA-Z_0-9]*\&*',r'',q)
#Delete the possible trailing #
r = re.sub(r'&$',r'',r)
print r