Question

我正在开发Silverlight 4应用程序并希望实现看似简单的任务：我有这个DataGrid：

<sdk:DataGrid x:Name="dg" Grid.Row="1"  Grid.ColumnSpan="2" Width="800" ItemsSource="{Binding SearchResults}" AutoGenerateColumns="False" >
                    <sdk:DataGrid.Columns>
                        <sdk:DataGridTemplateColumn SortMemberPath="Name" Header="Name" CellTemplate="{StaticResource SearchGridNameFieldtemplate}">

                        </sdk:DataGridTemplateColumn>
                        <sdk:DataGridTemplateColumn SortMemberPath="samAccountName" Header="Kontoname" CellTemplate="{StaticResource SearchGridAccountNameFieldtemplate}">

                        </sdk:DataGridTemplateColumn>

                        <sdk:DataGridTextColumn Header="Description" 
            Binding="{Binding Principal.Description}" />
                        <sdk:DataGridTextColumn Header="Container" 
            Binding="{Binding Principal.ContainerDN}" />

                    </sdk:DataGrid.Columns>
                </sdk:DataGrid>

现在我正在为TemplateColumn使用DataTemplate，它使用像这样的工具包Contextmenu

<DataTemplate x:Key="DirectoryUserSearchItemViewModel"  >
                                    <StackPanel Orientation="Horizontal">
                                        <controlsInputToolkit:ContextMenuService.ContextMenu>
                                            <controlsInputToolkit:ContextMenu>
                                                <controlsInputToolkit:MenuItem Header="Eigenschaften" Command="{Binding EditItem}" Visibility="{Binding User.DistinguishedName, Converter={StaticResource UserPermissionVisibilityConverter},ConverterParameter=1;8}" CommandParameter="{Binding User}">
                                                    <controlsInputToolkit:MenuItem.Icon>
                                                        <Rectangle Width="16" Height="16" Fill="{StaticResource MoveUpBrush}"/>
                                                    </controlsInputToolkit:MenuItem.Icon>
                                                </controlsInputToolkit:MenuItem>
                                                <controlsInputToolkit:MenuItem Header="User endgültig löschen" Command="{Binding HardDeleteAccount}" Visibility="{Binding HardDeleteCommandVisibility}" CommandParameter="{Binding User}">
                                                    <controlsInputToolkit:MenuItem.Icon>
                                                        <Rectangle Width="16" Height="16" Fill="{StaticResource MoveUpBrush}"/>
                                                    </controlsInputToolkit:MenuItem.Icon>
                                                </controlsInputToolkit:MenuItem>
                                                <controlsInputToolkit:MenuItem Header="Externe Anwendung ausführen" Command="{Binding ExecuteExternalApplication}" CommandParameter="{Binding User}">
                                                    <controlsInputToolkit:MenuItem.Icon>
                                                        <Rectangle Width="16" Height="16" Fill="{StaticResource MoveUpBrush}"/>
                                                    </controlsInputToolkit:MenuItem.Icon>
                                                </controlsInputToolkit:MenuItem>
                                            </controlsInputToolkit:ContextMenu>
                                        </controlsInputToolkit:ContextMenuService.ContextMenu>
                                        <TextBlock Text="{Binding Principal.Name}"/>
                                    </StackPanel>
                                </DataTemplate>

这里有趣的部分：如果我想能够在一行中的任何地方右键单击并激活上下文菜单，我是否真的必须复制粘贴整个上下文菜单datatemplate FOR EACH列？我不能将它设置为整行吗？ stackoverflow上的其他帖子似乎没有给出这个特定问题的答案。

Answer 1

您可以尝试添加列名，然后调用ContextMenuService.SetContextMenu将ContextMenu添加到其他列。

下一个挑战是确定右键单击了哪一列。

相关帖子：
How to get the Owner of the ContextMenu (from Silverlight 4 toolkit)?
Silverlight Toolkit ContextMenu: Which control was right-clicked?

Answer 2

根据帖子https://stackoverflow.com/a/8795056/451495的建议您可以使用以下内容：

public partial class Page1 : UserControl
{
    public Page1()
    {
        InitializeComponent();
        Loaded += OnLoaded;
        Grid1.LoadingRow += Grid1OnLoadingRow;
    }

    private void Grid1OnLoadingRow(object sender, DataGridRowEventArgs e)
    {
        var contextMenu = new ContextMenu();
        var deleteMenuItem = new System.Windows.Controls.MenuItem { Header = "text" };
        contextMenu.Items.Add(deleteMenuItem);
        ContextMenuService.SetContextMenu(e.Row, contextMenu);
    }
}

Silverlight DataGrid：整个Row上的Toolkit ContextMenu

2 个答案: