Question

我有以下REST get Request成功运行：

enter image description here

结果是我想要解析的XML文档。我在Java中尝试过相同的东西：

我使用以下代码：

public void getRootService() throws ClientProtocolException, IOException {

    HttpGet httpGet = new HttpGet("https://localhost:9443/ccm/rootservices");
    httpGet.setHeader("Accept", "text/xml");
    HttpResponse response = client.execute(httpGet);
    HttpEntity entity = response.getEntity();
    InputStream in = entity.getContent();
    String projectURL = XMLDocumentParser.parseDocument(in);

    System.out.println(projectURL);
    HttpGet getProjectsRequest = new HttpGet("https://localhost:9443/ccm/process/project-areas");
    getProjectsRequest.setHeader("Content-Type", "application/xml;charset=UTF-8");
    getProjectsRequest.setHeader("Accept-Charset", "UTF-8");
    getProjectsRequest.setHeader("Accept", "application/xml");


    ResponseHandler<String> handler = new BasicResponseHandler();
    String projectResponse = client.execute(getProjectsRequest, handler);
    //String projectResponse = client.execute(getProjectsRequest, handler);

    System.out.println(projectResponse);

}

但我该如何进行身份验证？我试图为“授权”值添加另一个标题字段，但后来我得不到相同的结果。

Answer 1

我认为你必须创建一个UsernamePasswordCredentials，类似于（未经测试的）;

CredentialsProvider credsProvider = new BasicCredentialsProvider();
credsProvider.setCredentials(
    new AuthScope("somehost", AuthScope.ANY_PORT), 
    new UsernamePasswordCredentials("username", "password"));

HttpClient httpclient = new DefaultHttpClient();
httpclient.setCredentialsProvider(credsProvider);

请参阅http://hc.apache.org/httpcomponents-client-ga/tutorial/html/authentication.html

编辑：
刚刚尝试了以下代码，并在我们的开发环境中成功调用了REST服务，该环境受BASIC保护。

public static void main(String[] args) throws ClientProtocolException, IOException {
    CredentialsProvider credsProvider = new BasicCredentialsProvider();
    credsProvider.setCredentials(
        new AuthScope("dev.*******.com", AuthScope.ANY_PORT), 
        new UsernamePasswordCredentials("*****", "******"));


    DefaultHttpClient client = new DefaultHttpClient();
    client.setCredentialsProvider(credsProvider);

    String url = "http://dev.******.com:18081/path/to/service/id.xml";

    HttpGet get = new HttpGet(url);
    ResponseHandler<String> handler = new BasicResponseHandler();
    String resp = client.execute(get, handler);

    System.out.println(resp);
  }

Answer 2

您可以向Authorization明确添加HttpRequestBase标题（HttpGet，HttpPost等的抽象类。）

此示例显示了如何制作基本授权值。

String unhashedString = userName + ":" + password;
String hashedString = Base64.encode(unhashedString); //This class doesn't exist, it's for demonstration purpose only.

HttpGet.setHeader("Authorization", "Basic " + hashedString);

在服务器中，你必须反过来（如果你正在进行自己的实现。

Answer 3

我实现此方法的方法是将会话与标准HTTP控制器一起使用。他们调用登录URL并发布用户和密码，并对会话进行身份验证。完成后，所有后续URL只需检查以确保会话已通过身份验证。

Answer 4

支持的身份验证机制取决于使用哪个Web服务器来托管Rational Team Concert。 Apache Tomcat服务器使用基本身份验证，而WebSphere Application Server支持基本身份验证和基于表单的身份验证。

您可以查看详细说明here

如何用Java创建这个REST get方法？

4 个答案: