我有一个应用程序从服务器下载图像,将它们存储在SD卡上,然后以幻灯片形式显示给用户。该应用程序有许多不同的幻灯片,用户可以查看。我的问题是,在我查看几个画廊后,我发现内存不足错误。我做了很多谷歌搜索,并阅读了Romain Guy的Avoiding Memory Leaks文章大约20次。我试图复制他的unbindDrawables()方法,但是无法在Gallery对象上调用removeAllViews()。我也尝试在所有位图上调用recycle()但是当我在适配器中的位图上执行时,应用程序会在打开图库时立即抛出错误。 我也尝试重新编码幻灯片,以便在适配器外部创建所有位图,然后将它们作为数组传递 - 这允许我遍历我的位图数组并在幻灯片中的onDestroy方法中对每个位图调用recycle()活动 - 但这实际上似乎使泄漏变得更糟。
以下是我的幻灯片活动的代码:
public class Slideshow extends Activity {
static String galleryId;
public static final int MSG_DOWNLOADED = 0;
static Handler handler;
static Gallery g;
static ArrayList<String> filePaths;
static String subFolder;
static ArrayList<String> imageToGet;
static LinearLayout pb;
static boolean firstTime = true;
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.slideshow);
Context context = getApplicationContext();
Bundle extras = getIntent().getExtras();
if(extras != null){
galleryId = extras.getString("galleryId");
}
pb = (LinearLayout) findViewById(R.id.progress);
handler = new Handler(){
@Override
public void handleMessage(Message msg){
switch (msg.what){
case MSG_DOWNLOADED:
g.setAdapter(new SlideshowAdapter(getApplicationContext(), R.id.gallery, filePaths));
pb.setVisibility(8);
if(firstTime){
Thread images = new Thread(){
public void run(){
ImageGallery gallery = XMLParser.getGalleryById(galleryId, false, getApplicationContext());
ArrayList<String> imageURLs = gallery.getImageURLs();
String subFolder = "gallery"+galleryId+"/";
getImages(imageURLs, subFolder, false);
}
};
images.start();
firstTime = false;
}
break;
}
}
};
ImageGallery gallery = XMLParser.getGalleryById(galleryId, false, context);
filePaths = gallery.getFilePaths();
ArrayList<String> imageURLs = gallery.getImageURLs();
subFolder = "gallery"+galleryId+"/";
g = (Gallery) findViewById(R.id.gallery);
if(filePaths.size() > 0){
String filePath = filePaths.get(0);
String url = imageURLs.get(0);
imageToGet = new ArrayList<String>();
imageToGet.add(url);
if(filePaths.size() == 1 ){
File file = new File(filePath);
if(!file.exists()){
Thread getFirstImage = new Thread(){
public void run(){
Log.d("ClubSlideshow getting only image", ""+imageToGet.get(0));
getImages(imageToGet, subFolder, false);
handler.sendEmptyMessage(MSG_DOWNLOADED);
}
};
getFirstImage.start();
}
}else if(filePaths.size()>1){
String filePath2 = filePaths.get(1);
String url2 = imageURLs.get(1);
File file = new File(filePath);
File file2 = new File(filePath2);
imageToGet.add(url2);
if(!file.exists()||!file2.exists()){
Thread getFirstImage = new Thread(){
public void run(){
getImages(imageToGet, subFolder, false);
handler.sendEmptyMessage(MSG_DOWNLOADED);
}
};
getFirstImage.start();
}
}
}
}
public void getImages(ArrayList<String> imageURLs, String subFolder, boolean force){
DataCache.downloadFromUrlArray(imageURLs, subFolder, force, getApplicationContext());
}
public class ImageThread implements Runnable{
public ImageThread(ArrayList<String> imageURLs, String subFolder, Boolean force){
getImages(imageURLs, subFolder, force);
}
public void run(){
}
}
@Override
protected void onDestroy(){
super.onDestroy();
g.setAdapter(null);
}
}
这是我的SlideshowAdapter类的代码:
public class SlideshowAdapter extends ArrayAdapter<String> {
int mGalleryItemBackground;
private Context mContext;
private ArrayList<String> images = new ArrayList<String>();
Bitmap bMap;
String filePath;
File file;
ImageView i;
public SlideshowAdapter(Context c, int resourceId, ArrayList<String> objects){
super(c, resourceId, objects);
this.mContext = c;
this.images = objects;
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
if(convertView !=null){
i = (ImageView) convertView;
}else{
i = new ImageView(mContext);
}
filePath = mContext.getFilesDir()+"/"+images.get(position);
file = new File(filePath);
if(file.exists()){
bMap = BitmapFactory.decodeFile(filePath);
i.setImageBitmap(bMap);
}
i.setScaleType(ImageView.ScaleType.FIT_CENTER);
return i;
}
}
有人能看到可能导致记忆问题的原因吗?
答案 0 :(得分:5)
实际上有几个问题:
getView
方法时都会如此
convertView为null请参阅this bug 答案 1 :(得分:1)
您可以尝试使用 scaledBitmap 来减少内存使用量
if(file.exists()){
bMap = BitmapFactory.decodeFile(filePath);
i.setImageBitmap(bMap);
}
到
if(file.exists()){
bMap = BitmapFactory.decodeFile(filePath);
bMap = Bitmap.createScaledBitmap(bMap, 100, 100, true);
i.setImageBitmap(bMap);
}
答案 2 :(得分:0)
尝试将图像存储在SD卡或设备内存中以避免此问题。