import pprint
full_key_list = set(["F1", "F2", "F3", "F4", "F5"]) # all expected field
filt_key_list = set(["F2", "F5"]) # fields should not be included
cont_list = [] # stores all filtered documents
read_in_cont1 = { "F1" : 1, "F2" : True, "F3" : 'abc', "F4" : 130, "F5" : 'X1Z'} # document1
read_in_cont2 = { "F1" : 2, "F2" : False, "F3" : 'efg', "F4" : 100, "F5" : 'X4Z'} # document1
read_in_cont3 = { "F1" : 3, "F2" : True, "F3" : 'acd', "F4" : 400, "F5" : 'X2Z'} # document1
# assume that read_in_conts contains list of documents
read_in_conts = [read_in_cont1, read_in_cont2, read_in_cont3]
for one_item in read_in_conts: # for each document in the list
cont_dict = {}
for key, value in one_item.iteritems():
if key not in filt_key_list: # if the field should be included
cont_dict[key] = value # add this field to the temporary document
cont_list.append(cont_dict)
pprint.pprint(cont_list)
输出:
[{'F1': 1, 'F3': 'abc', 'F4': 130},
{'F1': 2, 'F3': 'efg', 'F4': 100},
{'F1': 3, 'F3': 'acd', 'F4': 400}]
这是我想要实现的目标:
给定一个原始的原始文档集合(即用于模拟的read_in_conts), 我需要过滤字段,以便它们不包含在进一步的过程中。以上 是我在Python中的实现。但是,我认为这太重了,期望看到 这项任务的清洁解决方案。
谢谢
答案 0 :(得分:4)
cont_list = [dict((k,v) for k,v in d.iteritems() if k not in filt_key_list)
for d in read_in_conts]
或者如果你想要一个稍微更具因素的版本:
filter_out_keys = lambda d, x: dict((k,v) for k,v in d.iteritems() if k not in x)
cont_list = [filter_out_keys(d, filt_key_list) for d in read_in_conts]
P.S。我建议改为filt_key_list
set()
- 它会使in
检查更快。
答案 1 :(得分:1)
def filter_dict(d, keys):
return dict((key, value) for key, value in d.iteritems() if key not in filt_key_list))
cont_list = [filter_dict(d, filt_key_list) for d in read_in_conts]
答案 2 :(得分:1)
你的代码很好。你可以稍微缩短一下:
# sets can be faster if `ignored_keys` is actually much longer
ignored_keys = set(["F2", "F5"])
# the inline version of your loop
# a dict comprehension inside a list comprehension
filtered = [{k : v for k,v in row.iteritems() if k not in ignored_keys}
for row in read_in_conts]