我会尝试将图片插入Oracle DataBase - 但它不起作用
(Sql server中的相同代码非常出色)
string sampleImage = PicNativ;
BinaryReader sampleBR = null;
FileStream sampleFS = null;
OracleConnection sampleConnection = null;
OracleCommand sampleCommand = null;
FileInfo sampleFI = null;
byte[] sampleArr = null;
try
{
if (EDIT_M == 1)
Oracle = "update Sex set Name = '" + txtC.Text.Trim() +
"',pic = @p_pic where ID like '" + txtC4.Text.Trim() + "'";
else
Oracle = "insert into Sex (Id,Code,Name,pic) values "+
"(Sex_Code.nextval,'" + txtA.Text.Trim() + "','" +
txtC.Text.Trim() + "', @p_pic )";
sampleFI = new FileInfo(sampleImage);
sampleFS = new FileStream(sampleImage, FileMode.Open, FileAccess.Read);
sampleBR = new BinaryReader(sampleFS);
sampleArr = sampleBR.ReadBytes((int)sampleFI.Length);
using (sampleConnection = new OracleConnection(Conect))
{
sampleConnection.Open();
using (sampleCommand = new OracleCommand())
{
sampleCommand.Connection = sampleConnection;
sampleCommand.CommandText = Oracle;
sampleCommand.Parameters.
Add("@p_pic", OracleDbType.Blob ).Value = sampleArr;
sampleCommand.ExecuteNonQuery();
}
}
}
finally
{
sampleBR.Close();
sampleFS.Close();
}
答案 0 :(得分:0)
如您所知,ORA-00936是一个缺失的表达式错误。在您的问题代码中,您在SQL语句中使用了绑定变量。在Oracle中,placeholder variable starts with a colon。因此,@p_pic
的正确格式为:@p_pic
。
在命名参数中使用&符号是Microsoft SQL Server。