冒充用户名和密码?

时间:2011-10-10 09:01:58

标签: c# console-application impersonation

WindowsIdentity identity = new WindowsIdentity(accessToken);
WindowsImpersonationContext context = identity.Impersonate();

 ...
context.Undo();

我在哪里声明管理员UserName和Passowrd?

accessToken 参数对我没有多大帮助......

我是否必须为其导入DLLS?

3 个答案:

答案 0 :(得分:22)

您需要获取用户的令牌。使用advapi32.dll中的p / invoke LogonUser

    [DllImport("advapi32.dll", SetLastError = true)]
    public static extern bool LogonUser(
            string lpszUsername,
            string lpszDomain,
            string lpszPassword,
            int dwLogonType,
            int dwLogonProvider,
            out IntPtr phToken);

示例:

IntPtr userToken = IntPtr.Zero;

bool success = External.LogonUser(
  "john.doe", 
  "domain.com", 
  "MyPassword", 
  (int) AdvApi32Utility.LogonType.LOGON32_LOGON_INTERACTIVE, //2
  (int) AdvApi32Utility.LogonProvider.LOGON32_PROVIDER_DEFAULT, //0
  out userToken);

if (!success)
{
  throw new SecurityException("Logon user failed");
}

using (WindowsIdentity.Impersonate(userToken))
{
  // do the stuff with john.doe's credentials
}

答案 1 :(得分:5)

它正是你必须使用的accessoken。要得到它,你需要调用LogonUser方法:

oops没有意识到我只是在这里有VB.net代码。想象一下它在C#;) 这里是c#

外部方法声明:

Private Declare Auto Function LogonUser Lib "advapi32.dll" (ByVal lpszUsername As [String], _
ByVal lpszDomain As [String], ByVal lpszPassword As [String], _
ByVal dwLogonType As Integer, ByVal dwLogonProvider As Integer, _
ByRef phToken As IntPtr) As Boolean

和执行:

_Token = New IntPtr(0)

Const LOGON32_PROVIDER_DEFAULT As Integer = 0
'This parameter causes LogonUser to create a primary token.
Const LOGON32_LOGON_INTERACTIVE As Integer = 2
Const LOGON32_LOGON_NEWCREDENTIALS As Integer = 9

_Token = IntPtr.Zero

' Call LogonUser to obtain a handle to an access token.
Dim returnValue As Boolean = LogonUser(_User, _Domain, _Password, LOGON32_LOGON_NEWCREDENTIALS, LOGON32_PROVIDER_DEFAULT, _Token)

If False = returnValue Then
     Dim ret As Integer = Marshal.GetLastWin32Error()
     Console.WriteLine("LogonUser failed with error code : {0}", ret)
     Throw New System.ComponentModel.Win32Exception(ret)
End If

_Identity = New WindowsIdentity(_Token)
_Context = _Identity.Impersonate()

答案 2 :(得分:2)

您需要P /调用LogonUser() API。它接受用户名,域名和密码并返回一个令牌。