Question

我有一个查询来从数据库中检索未付款项，即总发票金额减去总付款金额。问题是，当没有发票付款时，这些只是不显示。我希望这些发票金额显示，其总付款金额为零。这是我的疑问：

SELECT DISTINCT Client.FirstName + ' ' + Client.LastName                   AS
                [Client Name],
                SUM(Invoices.InvoiceAmount)                                AS
                [Total Invoice Amounts],
                SUM(ClientPayments.PaymentAmount)                          AS
                [Total Amount Paid],
                SUM(Invoices.InvoiceAmount - ClientPayments.PaymentAmount) AS
                [Outstanding Payment Amount]
FROM   Invoices
       INNER JOIN ClientPayments
         ON Invoices.InvoiceNumberID = ClientPayments.InvoiceNumberID
       INNER JOIN Client
         ON Invoices.ClientNumberID = Client.ClientNumberID
GROUP  BY Client.FirstName,
          Client.LastName

谢谢，艾米

Answer 1

尝试将INNER JOIN更改为LEFT JOIN以进行查询中的第一次加入

Answer 2

它可能是基于进行左连接，但如果您有一张已多次付款的发票（部分付款），您会得到虚假结果吗？那些“Sum”方程式会计算发票金额TWICE ex：每个部分付款一个吗？我会尝试如下。

SELECT 
      C.ClientNumberID,
      C.FirstName + ' ' + C.LastName AS ClientName, 
      SUM( I.InvoiceAmount ) TotalInvoices, 
      SUM( CP.PaymentAmount ) AS TotalAmountPaid, 
      SUM( I.InvoiceAmount ) - SUM( CP.PaymentAmount ) AS OutstandingPaymentAmount
   FROM
      Invoices I
         JOIN Clients C
            on I.ClientNumberID = C.ClientNumberID

      LEFT JOIN ClientPayments CP
         on I.InvoiceNumberID = CP.InvoiceNumberID
   GROUP BY
      I.ClientNumberID
   ORDER BY
      C.LastName,
      C.FirstName

请注意我的GROUP BY是客户编号...如果您有5个客户“William Smith”或“Robert Brown”可以被视为“通用名称”，那么会发生什么情况。你不想给威廉史密斯一个声明说他欠他5000美元的全部费用，而发票实际上是与其他“威廉史密斯”客户分开的。那么，ORDER BY会把它们放到你需要的任何顺序......或者基于顶部最大收藏的优秀数量下降。

SQL查询 - 未付款

2 个答案: