Question

我正在尝试设置一个函数来计算两部电影的相似度。有预先存在的词典，以电影为关键，导演，流派或主要演员都是价值观。有三个演员词典（每部电影的3个主要演员列出）。代码大多数工作正常，但有时我得到的分数大于我应该得到的分数。

# create a two-variable function to deterime the FavActor Similarity score: 
def FavActorFunction(film1,film2):

    #set the result of the FavActor formula between two films to a default of 0.
    FavActorScore = 0
    #add 3 to the similarity score if the films have the same director.
    if direct[film1] == direct[film2]:
        FavActorScore += 3
    #add 2 to the similarity score if the films are in the same genre.
    if genre[film1] == genre[film2]:
        FavActorScore += 2
    #add 5 to the similarity score for each actor they have in common.
    if actor1[film1] == actor1[film2] or actor2[film2] or actor3[film2]:
        FavActorScore += 5
    if actor2[film1] == actor1[film2] or actor2[film2] or actor3[film2]:
        FavActorScore += 5     
    if actor3[film1] == actor1[film2] or actor2[film2] or actor3[film2]:
        FavActorScore += 5
    #print the resulting score.                    
    return FavActorScore

我的假设是，在计算他们共同的演员时，它会计算两次事情。有没有办法修改这部分代码，以便得到更准确的结果？

if actor1[film1] == actor1[film2] or actor2[film2] or actor3[film2]:   
    FavActorScore += 5
if actor2[film1] == actor1[film2] or actor2[film2] or actor3[film2]:  
    FavActorScore += 5     
if actor3[film1] == actor1[film2] or actor2[film2] or actor3[film2]:  
    FavActorScore += 5

Answer 1

尝试使用in条件：

if actor1[film1] in (actor1[film2], actor2[film2], actor3[film2]):
   FavActorScore += 5 
if actor2[film1] in ( actor1[film2], actor2[film2], actor3[film2]):
   FavActorScore += 5
if actor3[film1] in (actor1[film2], actor2[film2], actor3[film2]):
   FavActorScore += 5

当你写a==b or c or d时，如果a等于b或者c为真，或者d为真，则如果a等于b或c或d则为真。

使用预先存在的词典添加到int值

1 个答案: