Question

我在rspec中为will_paginate编写测试时遇到问题。问题是我有一个拥有许多宠物的主人的模型。这会导致一个看起来像这样的factories.rb文件：



Factory.define :owner do |owner|
  owner.personid              "1111111"
  owner.firstname             "Nisse"
  owner.lastname              "Gunnarsson"
  owner.street                "Street"
  owner.postaladress          "38830"
  owner.town                  "Town"
  owner.phone                 "555-5555"
  owner.mobile                "555-5556"
  owner.email                 "nisse@test.com"
  owner.reminder              true
end

Factory.define :pet do |pet|
  pet.name                    "Hedvig"
  pet.specie                  "Rabbot"
  pet.breed                   "Lowen/vadur"
  pet.colour                  "Madagaskar"
  pet.association             :owner
end

Factory.define :owner do |owner| owner.personid "1111111" owner.firstname "Nisse" owner.lastname "Gunnarsson" owner.street "Street" owner.postaladress "38830" owner.town "Town" owner.phone "555-5555" owner.mobile "555-5556" owner.email "nisse@test.com" owner.reminder true end Factory.define :pet do |pet| pet.name "Hedvig" pet.specie "Rabbot" pet.breed "Lowen/vadur" pet.colour "Madagaskar" pet.association :owner end

在我的测试中我有

describe "Get show" do
  before(:each) do
  @owner = Factory(:owner)
  30.times do
    #@owner.pets << Factory.build(:pet)
    @pet = Factory.build(:pet, :owner => @owner)
    #@owner.pets << @pet
  end      
end

it "should have an element for each pet" do
   get :show, :id => @owner
   @owner.pets[0..2].each do |pet|
     response.should have_selector("td", :content => pet.name)
   end
   response.should have_selector("td", :content => "Hedvig")
 end

 it "should paginate pets" do
   get :show, :id => @owner
   response.should have_selector("div.pagination")
   response.should have_selector("span.disabled", :content => "Previous")
   response.should have_selector("a", :href => "/pets?page=2",
                                      :content => "2")
   response.should have_selector("a", :href => "/pets?page=2",
                                      :content => "Next")
 end

end

所以我用工厂创建了一个所有者，没问题。我可以通过describe "Get show" do before(:each) do @owner = Factory(:owner) 30.times do #@owner.pets << Factory.build(:pet) @pet = Factory.build(:pet, :owner => @owner) #@owner.pets << @pet end end it "should have an element for each pet" do get :show, :id => @owner @owner.pets[0..2].each do |pet| response.should have_selector("td", :content => pet.name) end response.should have_selector("td", :content => "Hedvig") end it "should paginate pets" do get :show, :id => @owner response.should have_selector("div.pagination") response.should have_selector("span.disabled", :content => "Previous") response.should have_selector("a", :href => "/pets?page=2", :content => "2") response.should have_selector("a", :href => "/pets?page=2", :content => "Next") end

获取所有者名称

我也可以创建一个拥有正确所有者（）的宠物，但我无法弄清楚如何用宠物填充所有者数组（@ owner.pets）。

如果我执行@ owner.pets.count，则为0。

应用程序工作正常，我只是无法弄清楚如何编写测试。我对rails和TDD都很陌生，但我想做得对。

如果我要添加更多信息，请告诉我。

干杯卡尔

Answer 1

首先，执行@pet = Factory.build(:pet, :owner => @owner)只会构建一个Pet对象，但永远不会将其保存到数据库中。您可能希望使用Factory.create(:pet, ...来实际保存它。

最初创建Owner对象时，@owner.pets数组为[]。如果您只是使用Factory.create在数据库中创建记录，那么技术上@owner有宠物，但@owner对象不知道它们，因为它已经在内存中{{1数组[]。

相反，试试这个：

.pets

这不仅会将其保存到数据库中，因此对数据库的任何新调用都是有效的（例如现在，如果你{1}}你回来了1），还有@owner.pets << Factory.create(:pet, :owner => @owner)数组在内存中将有一个有效的Pet对象。

使用factory_girl进行RSpec测试，并使用will_paginate进行关联对象

1 个答案: